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Setler [38]
3 years ago
12

If there are 2.54cm in an inch , how many inches are in 14.8cm?

Chemistry
2 answers:
klasskru [66]3 years ago
6 0
5.8267716535 inches in 14.8cms
Afina-wow [57]3 years ago
4 0
The answer is 7 inches
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What is the volume of a liquid that has a density 3.65g/ml and a mass of 5.61g
Lorico [155]

Answer:

<h2>1.54 mL</h2>

Explanation:

The volume of a substance when given the density and mass can be found by using the formula

volume =  \frac{mass}{density} \\

From the question we have

volume =  \frac{5.61}{3.65}  \\  =1.536986...

We have the final answer as

<h3>1.54 mL</h3>

Hope this helps you

3 0
3 years ago
ammonium nitrate, which is prepared from nitric acid, is used as a nitrogen fertilizer. determine the percent composition of amm
Alina [70]

Answer:

Ammonium nitrate, (NH4NO3), a salt of ammonia and nitric acid, used widely in fertilizers and explosives. The commercial grade contains about 33.5 percent nitrogen, all of which is in forms utilizable by plants; it is the most common nitrogenous component of artificial fertilizers.

5 0
3 years ago
What is the percent by mass of oxygen in carbon dioxide (CO2)?
wariber [46]

Answer:

= 72.73%

Explanation:

The percentage by mass of an element is given by;

% element = total mass of element in compounds/molar mass of compound × 100

The mass of oxygen in carbon dioxide = 32 g

Molar mass of CO2 = 44 g

Therefore;

% of O2 = 32/44 × 100%

             <u>= 72.73%</u>

8 0
3 years ago
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densk [106]
When I was on the phone with my bio teacher I asked she said endothermic
3 0
3 years ago
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What are the concentrations of h3o+ and oh− in tomatoes that have a ph of 4.10?
IRINA_888 [86]

Answer : The concentration of H_3O^+ and OH^- are 7.94\times 10^{-5} and 1.258\times 10^{-10} respectively.

Solution : Given,

pH = 4.10

pH : pH is defined as the negative logarithm of hydronium ion concentration.

Formula used : pH=-log[H_3O^+]

First we have to calculate the hydronium ion concentration by using pH formula.

4.10=-log[H_3O^+]

[H_3O^+]=antilog(-4.10)

[H_3O^+]=7.94\times 10^{-5}

Now we have to calculate the pOH.

As we know, pH+pOH=14

4.10+pOH=14

pOH=9.9

Now we have to calculate the hydroxide ion concentration.

pOH=-log[OH^-]

9.9=-log[OH^-]

[OH^-]=antilog(-9.9)

[OH^-]=1.258\times 10^{-10}

Therefore, the concentration of H_3O^+ and OH^- are 7.94\times 10^{-5} and 1.258\times 10^{-10} respectively.

5 0
3 years ago
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