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Sveta_85 [38]
1 year ago
15

An object that is dropped from a height H falls with a constant acceleration of g. The final

Physics
1 answer:
GuDViN [60]1 year ago
4 0

The height need to change by 4 to double the final velocity.

<h3>Final velocity of the object</h3>

The final velocity of an object during a free fall is related to maximum height of fall as given the equation below.

v = √2gh

v² = 2gh

v²/h = 2g

v₁²/h₁ = v₂²/h₂

when v₂ = 2v₁, change in height is calculated as;

h₂ = h₁v₂²/v₁²

h₂ = (h₁ (2v₁)²) / (v₁)²

h₂ = 4h₁v₁² / v₁²

h₂ = 4h₁

Thus, the height need to change by 4 to double the final velocity.

Learn more about final velocity here: brainly.com/question/25905661

#SPJ1

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Two capacitors have the same size of plates and the same distance 4 mm between the plates The potentials of the two plates in ca
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Answer:

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Explanation:

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we reduce the magnitudes to the SI system

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we calculate

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8 0
3 years ago
In this circuit the battery provides 3 V, the resistance R1 is 7 Ω, and R2 is 5 Ω. What is the current through resistor R2? Give
sveta [45]

Answer:

The current pass the R_2 is  I  = 0.25 A

Explanation:

The diagram for this question is shown on the first uploaded image  

From the question we are told that

    The voltage  is  V =  3V

     The first resistance is  R_1 = 7 \Omega

     The second resistance is  R_2 = 5 \Omega

Since the resistors are connected in series their equivalent resistance is  

       R_{eq} =  R_1 +R_2

Substituting values

         R_{eq} = 7 + 5

         R_{eq} = 12 \Omega

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Substituting values  

      I  =  \frac{3}{12}

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Answer:

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