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The magnitude of force on the elevator cable that would be needed to lower the cat/elevator pair is 198 Newton.
<u>Given the following data:</u>
- Acceleration = 2

To determine the magnitude of force on the elevator cable that would be needed to lower the cat/elevator pair, we would apply Newton's Second Law of Motion:
First of all, we would calculate the total mass of the cat/elevator pair.

Total mass = 99 kilograms
Mathematically, Newton's Second Law of Motion is given by this formula;

Substituting the given parameters into the formula, we have;

Net force = 198 Newton
Read more here: brainly.com/question/24029674
Answer:
- The gravity does a work of - 117.6 Joules.
- The tension does not do work as the force is perpendicular to the direction of motion at any point in the trajectory.
Explanation:
The work done by the gravity simply is the difference in gravitational potential energy multiplied by -1:

where m is the mass of the ball, g is the acceleration due to gravity,
is the final height and
is the initial height.
So, if the radius is 2.00 m, then the difference of height will be 4 meters:



As the tension is perpendicular to the velocity of the ball, the force is always perpendicular to the direction of motion. So, the differential of work will be:

= 27.777
Explanation:
A kilometer has 1,000 meters, and an hour has 3,600 seconds, so 100 kilometers per hour is: 100 x 1,000 / 3,600 = 27.777... m/s.