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Pie
3 years ago
5

Describe how the graph of y = |x - 2| - 5 is a transformation of the graph of y = |x|. Use terms such as "shifted", "reflected",

"stretched", or "compressed".
Mathematics
1 answer:
valentinak56 [21]3 years ago
3 0

Answer:

The original graph was shifted 2 units to the left and 5 units down.

Step-by-step explanation:

y = |x|

From this, we go to: y = |x - 2|.

When we want to shift a function f(x) a units to the left, we find f(x - a). So first, the graph was shifted 2 units to the left.

y = |x - 2|.

From this, we go to: y = |x - 2| - 5.

Shifting a function f(x) down b units is the same as finding f(x) - b, so the second transformation was shifting the graph 5 units down.

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Assume that thermometer readings are normally distributed with a mean of 0 degrees C and a standard deviation of 1.00 degrees C.
Cerrena [4.2K]

Answer:

The probability of getting a reading between -1.42 degree C and 1.61 degree C is 0.8685.

Step-by-step explanation:

We are given that

Mean,\mu=0 degree C

Standard deviation, \sigma=1 degree C

We have to find the probability of the reading between -1.42 and 1.61.

P(-1.42

P(-1.42

P(-1.42

Using the formula

P(a

P(-1.42

P(-1.42

Hence, the probability of getting a reading between -1.42 degree C and 1.61 degree C is 0.8685.

4 0
3 years ago
Identify the type of function that models the situation below: A can of coffee is supposed to contain one pound of coffee. Which
ss7ja [257]
1 - x

Difference means subtraction. x is the actual weight that we don't know.
3 0
3 years ago
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OAA', OBB', and OCC' are straight lines. Triangle ABC is mapped onto Triangle A'B'C' by an enlargement with center O. What is th
bazaltina [42]

Answer:

(D) 2

Step-by-step explanation:

The scale factor of the enlargement of ΔABC to ΔA'B'C' is given by the ratio of the length of the corresponding sides of ΔA'B'C' and ΔABC

Therefore, we have;

The \ scale \ factor = \dfrac{Length \ of \overline  {B'C'}}{Length \ of \overline {BC}} =  \dfrac{Length \ of \overline  {A'C'}}{Length \ of \overline {AC}} =  \dfrac{Length \ of \overline  {A'B'}}{Length \ of \overline {AB}}

\dfrac{Length \ of \overline  {B'C'}}{Length \ of \overline {BC}} =  \dfrac{2 \ units}{1 \ unit} = 2

\dfrac{Length \ of \overline  {A'C'}}{Length \ of \overline {AC}} =  \dfrac{4 \ units}{2 \ units} = 2

\dfrac{Length \ of \overline  {A'B'}}{Length \ of \overline {AB}} =  \dfrac{2 \cdot \sqrt{5}  \ units}{\sqrt{5}  \ units} = 2

Therefore, the scale factor = 2

6 0
3 years ago
This net will be folded to form a solid.
emmasim [6.3K]

Answer:

2,5, and 6

Step-by-step explanation:

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4 years ago
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Round the following percentages to one decimal place.0.698%53.123%0.075%34.337%3.876%
balandron [24]

To round off a given number in decimals to one decimal place (1 dp), we simply take the figure right after the decimal and approximate the remaining after it. If the second number after the decimal is a significant number (5 and above) we make it 1 and add to the number right after the decimal. If its NOT a significant number, we simply disregard it. The solutions therefore are;

ANSWER:

\begin{gathered} \text{Rounded to one decimal place;} \\ (1)0.698\%\approx0.7 \\ (2)53.123\%\approx53.1 \\ (3)0.075\%\approx0.1 \end{gathered}

Notice how the number in (1) becomes 0.7, after taking the next number (which is 9) and adding it as 1 to the number after the decimal (which is 6). The same applies to the number in (3).

\begin{gathered} (4)34.337\%\approx34.3 \\ (5)3.876\%\approx3.9 \end{gathered}

4 0
1 year ago
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