Answer:
3 dogs and 2 cats.
Step-by-step explanation:
In this case we can solve it using a 2x2 system of equations, like this:
let x: number of cats
let y: number of dogs
So:
42.5 * x + 64 * y = 277
35.5 * x + 50.5 * y = 222.5 => x = (222.5 - 50.5 * y) /35.5
Replacing, we are left with that:
42.5 * (222.5 - 50.5 * y) /35.5 + 64 * y = 277
266.37- 60.45 * y + 64 * y = 277
64 * y - 60.45 * y = 277 - 266.37
3.55 * y = 10.63
y = 10.63 / 3.55
y = 2.99, about 3
Now to calculate x:
x = (222.5 - 50.5 * 3) /35.5
x = 2
Which means that it has a total of 3 dogs and 2 cats.
The equation that expresses the relationship between the number of boxes, b and the number or cans, c would be c = 48b. This is because the number or cans shipped would be the dependent variable to the problem as it is dependent on the number or boxes that ship along with. So if one ships 2 boxes then the number of cans that would be shipped would need to match the final output of cans which is 96, and using the equation, c = 49b it does.
c = 48b
96 = 48(2)
96 = 96.
Technically the first option will also be correct but usually the variable in an algebraic expression comes after the coefficient.
Answer:
I see, you have to hhh.
Step-by-step explanation:
The answer should be 15/24 of an ouce beacause 35 minus 5 ounces because the box weighs 5 ounces when it is empty. Then, you need to do 30 dibided by to to get 30/48 which is reduced to 15/24.
