Answer: Option (d) is the correct answer.
Explanation:
According to the given situation, mass of compound will be calculated as follows.
Mass of compound = mass of flask and condensed vapor - mass of flask
= 115.23 - 114.85
= 0.38 g
Volume (V) = 255 mL = 
(as 1 ml = 
)
Pressure (P) = 101325 Pa
Temperature = 
= (100 + 273) K = 373 K
Now, according to the ideal gas equation, PV = nRT
and, moles of compound n = 
= 
= 0.008332 mol
As, molar mass of compound = 
= 
= 46 g/mol
Therefore, the compound is 
(molar mass = 12 x 2 + 5 x 1 + 16 + 1 = 46 g/mol).
Thus, we can conclude that out of the given options the liquid could be .
for one you could do a bell, ringing noise, then say someone rang it.
For two you could do tunnel, echoing, then say someone yelled and it echoed.
for three you could do a bowl, ringing, spoon hitting it
hope i could help
<span>A) 2NaOH -> 2Na + O2 + H2
is not correct since Na is unstable
B) 2NaOH -> 2Na + H2O + 1/2O2
is not correct since Na is unstable
C) 2NaOH -> Na2O + H2O
is correct since N2O is stable
D) 2NaOH -> 2Na + H2O2
is not correct since Na is unstable</span>
Answer : The mass of oxygen per gram of sulfur for sulfur dioxide and sulfur trioxide is, 0.997 g and 1.5 g respectively.
Explanation : Given,
Mass of oxygen in sulfur dioxide = 3.49 g
Mass of sulfur in sulfur dioxide = 3.50 g
Mass of oxygen in sulfur trioxide = 9.00 g
Mass of sulfur in sulfur trioxide = 6.00 g
Now we have to calculate the mass of oxygen per gram of sulfur for sulfur dioxide and sulfur trioxide.
Mass of oxygen per gram of sulfur for sulfur dioxide = 
Mass of oxygen per gram of sulfur for sulfur dioxide = 
and,
Mass of oxygen per gram of sulfur for sulfur trioxide =
Mass of oxygen per gram of sulfur for sulfur trioxide = 
Thus, the mass of oxygen per gram of sulfur for sulfur dioxide and sulfur trioxide is, 0.997 g and 1.5 g respectively.
