In the first reaction, Gold (Au) gets 3 electrons and became Gold. In the second reaction, Iodine (I) loses 2 electrons and became Iodine.
<h3>What are cations and anions?</h3>
When the atom loses the election then it is called a cation and when it gains the electron is called an anion.
Two reactions are given.
First reaction;
Au³⁺ + 3e⁻ ⇒ Au
In the first reaction, Gold (Au) gets 3 electrons and became Gold.
Second reaction;
2I⁻ ⇒ I₂ + 2e⁻
In the second reaction, Iodine (I) loses 2 electrons and became Iodine.
More about the cation and the anion link is given below.
brainly.com/question/1659592
Answer:
The answer to your question is:
x = -8; y = 1 ; z = -4
Step-by-step explanation:
Δ = ![\left[\begin{array}{ccc}-5&1&-4\\2&4&3\\6&-3&-2\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-5%261%26-4%5C%5C2%264%263%5C%5C6%26-3%26-2%5Cend%7Barray%7D%5Cright%5D)
= 40 + 24 + 18 - (-4 + 45 - 96)
= 82 + 55
= 137
Δx = ![\left[\begin{array}{ccc}60&1&-4\\-12&4&3\\-52&-3&-2\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D60%261%26-4%5C%5C-12%264%263%5C%5C-52%26-3%26-2%5Cend%7Barray%7D%5Cright%5D)
= - 480 - 144 - 156 - ( 24 - 540 + 832)
= -780 -316
= - 1096
Δy = ![\left[\begin{array}{ccc}-5&1&-4\\2&4&3\\6&-3&-2\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-5%261%26-4%5C%5C2%264%263%5C%5C6%26-3%26-2%5Cend%7Barray%7D%5Cright%5D)
= 40 + 24 + 18 - ( - 4 + 45 - 96)
= 82 + 55
= 137
Δz = ![\left[\begin{array}{ccc}-5&1&60\\2&4&-12\\6&-3&-52\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-5%261%2660%5C%5C2%264%26-12%5C%5C6%26-3%26-52%5Cend%7Barray%7D%5Cright%5D)
= 1040 - 360 - 72 - ( - 104 - 180 + 1440)
= 608 - 1156
= -548
x = -1096/ 137 = -8
y = 137 / 137 = 1
z = -548 / 137 = -4
Step-by-step explanation:
Note: Question does not indicate if probability required is for weight to exceed or below 3000 lbs. So choose appropriate answer accordingly (near the end)
Using the usual notations and formulas,
mean, mu = 3550
standard deviation, sigma = 870
Observed value, X = 3000
We calculate
Z = (X-mu)/sigma = (3000-3550)/870 = -0.6321839
Probability of weight below 3000 lbs
= P(X<3000) = P(z<Z) = P(z<-0.6321839) = 0.2636334
Answer:
Probability that a car randomly selected is less than 3000
= P(X<3000) = 0.2636 (to 4 decimals)
Probability that a car randomly selected is greater than 3000
= 1 - P(X<3000) = 1 - 0.2636 (to 4 decimals) = 0.7364 (to 4 decimals)
Answer:
ok hold on
Step-by-step explanation: