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3 years ago

Sally earns $37.00 for 4 hours of babysitting.At this rate,how much more would she earn for 9 hours of babysitting? Show work.

Mathematics

1 answer:

Gennadij [26K]3 years ago

3 0

So if you divide 37 by 4 you get the rate per hour which is 9.25 so if you multiply 9 times 9.25 you would get 83.25

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Plz help due tommorow big grade

Korvikt [17]

It would take 4750 because 1L is 5000 ml and 5000-250=4750. Use the web to do it in metric measurements.

3 0

3 years ago

4 1/7% = <br> what in decimal form

kykrilka [37]

Answer:

.0417

Step-by-step explanation:

.0 is 10th's place so if we had 50 percent it would be .5

.00 is ones place so 4 percent would be .04

.0000 is where fractions come in so 3 3/4 would be .00375

6 0

3 years ago

Read 2 more answers

can someone show me how to find the general solution of the differential equations? really need to know how to do it for the upc

mariarad [96]

The first equation is linear:

$x\dfrac{\mathrm dy}{\mathrm dx}-y=x^2\sin x$

Divide through by $x^2$ to get

$\dfrac1x\dfrac{\mathrm dy}{\mathrm dx}-\dfrac1{x^2}y=\sin x$

and notice that the left hand side can be consolidated as a derivative of a product. After doing so, you can integrate both sides and solve for $y$ .

$\dfrac{\mathrm d}{\mathrm dx}\left[\dfrac1xy\right]=\sin x$
$\implies\dfrac1xy=\displaystyle\int\sin x\,\mathrm dx=-\cos x+C$
$\implies y=-x\cos x+Cx$

- - -

The second equation is also linear:

$x^2y'+x(x+2)y=e^x$

Multiply both sides by $e^x$ to get

$x^2e^xy'+x(x+2)e^xy=e^{2x}$

and recall that $(x^2e^x)'=2xe^x+x^2e^x=x(x+2)e^x$ , so we can write

$(x^2e^xy)'=e^{2x}$
$\implies x^2e^xy=\displaystyle\int e^{2x}\,\mathrm dx=\frac12e^{2x}+C$
$\implies y=\dfrac{e^x}{2x^2}+\dfrac C{x^2e^x}$

- - -

Yet another linear ODE:

$\cos x\dfrac{\mathrm dy}{\mathrm dx}+\sin x\,y=1$

Divide through by $\cos^2x$ , giving

$\dfrac1{\cos x}\dfrac{\mathrm dy}{\mathrm dx}+\dfrac{\sin x}{\cos^2x}y=\dfrac1{\cos^2x}$
$\sec x\dfrac{\mathrm dy}{\mathrm dx}+\sec x\tan x\,y=\sec^2x$
$\dfrac{\mathrm d}{\mathrm dx}[\sec x\,y]=\sec^2x$
$\implies\sec x\,y=\displaystyle\int\sec^2x\,\mathrm dx=\tan x+C$
$\implies y=\cos x\tan x+C\cos x$
$y=\sin x+C\cos x$

- - -

In case the steps where we multiply or divide through by a certain factor weren't clear enough, those steps follow from the procedure for finding an integrating factor. We start with the linear equation

$a(x)y'(x)+b(x)y(x)=c(x)$

then rewrite it as

$y'(x)=\dfrac{b(x)}{a(x)}y(x)=\dfrac{c(x)}{a(x)}\iff y'(x)+P(x)y(x)=Q(x)$

The integrating factor is a function $\mu(x)$ such that

$\mu(x)y'(x)+\mu(x)P(x)y(x)=(\mu(x)y(x))'$

which requires that

$\mu(x)P(x)=\mu'(x)$

This is a separable ODE, so solving for $\mu$ we have

$\mu(x)P(x)=\dfrac{\mathrm d\mu(x)}{\mathrm dx}\iff\dfrac{\mathrm d\mu(x)}{\mu(x)}=P(x)\,\mathrm dx$
$\implies\ln|\mu(x)|=\displaystyle\int P(x)\,\mathrm dx$
$\implies\mu(x)=\exp\left(\displaystyle\int P(x)\,\mathrm dx\right)$

and so on.

6 0

3 years ago

How would I find the answer?

Montano1993 [528]

Answer:

tangent

Step-by-step explanation:

tan = opposite/adjacent

the side opposite base of ladder angle is x, and the side adjacent is 15

8 0

3 years ago

Find the mid point of p(3,5) and q-2,13

Vsevolod [243]

Answer:

(0.5, 9 )

Step-by-step explanation:

Using the midpoint formula

[ 0.5(x₁ + x₂ ), 0.5(y₁ + y₂ ) ]

with (x₁, y₁ ( = (3, 5) and (x₂, y₂ ) = ( - 2, 13 )

midpoint = [0.5(3 - 2), 0.5(5 + 13) ] = [0.5(1), 0.5(18) ] = (0.5, 9 )

3 0

3 years ago