All categories

3 years ago

Does anybody know how to find the volume of. a prism. please help

Mathematics

1 answer:

olganol [36]3 years ago

7 0

V = [1/2 x 5 x side x apothem] x height of the prism.
V=[ 1/2 x 5 x 7.1 x 5] x 15
V= 88.75 x 15
V= 1331.25

You might be interested in

Which equations are equivalent to Y=2/3X-4 when written in slope-intercept form? Check all that apply. A =3X-2Y=4. B=2X-3Y=12. C

klemol [59]

Answer:

B and C

Step-by-step explanation:

Rearrange each equation into slope- intercept form

3x - 2y = 4 ( subtract 3x from both sides )

- 2y = - 3x + 4 ( divide all terms by - 2 )

y = $\frac{3}{2}$ x - 2 ← not equivalent

2x - 3y = 12 ( subtract 2x from both sides )

- 3y = - 2x + 12 ( divide all terms by - 2 )

y = $\frac{2}{3}$ x - 4 ← equivalent

- 4(2x - 3y ) = - 48 ( divide both sides by - 4 )

2x - 3y = 12 ← same as B ⇒ equivalent

2(x + 6) = 3y

3y = 2x + 12 ( divide all terms by 3 )

y = $\frac{2}{3}$ x + 4 ← not equivalent

2x - 3y = 4 ( subtract 2x from both sides )

- 3y = - 2x + 4 ( divide all terms by - 3 )

y = $\frac{2}{3}$ x - $\frac{4}{3}$ ← not equivalent

4 0

3 years ago

Read 2 more answers

A dance school has 54 students who learn salsa

Archy [21]

They should be 54 students who know how to salsa

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Please help me! Find the number x such that f(x) =1

STatiana [176]

Answer:

Step-by-step explanation:

We have the piecewise function:

$f(x) = \left\{ \begin{array}{ll} -\frac{1}{2}x-1 & \quad x \leq -2 \\ x & \quad x > -2 \end{array} \right.$

And we want to find x such that f(x)=1.

So, let's substitute 1 for f(x):

$1 = \left\{ \begin{array}{ll} -\frac{1}{2}x-1 & \quad x \leq -2 \\ x & \quad x > -2 \end{array} \right.$

This has two equations. So, we can separate them into two separate cases. Namely:

$1=-\frac{1}{2}x-1\text{ or } 1=x$

Let's solve for x in each case.

Case I:

We have:

$1=-\frac{1}{2}x-1$

Add 1 to both sides:

$2=-\frac{1}{2}x$

Let's cancel out the fraction by multiplying both sides by -2. So:

$2(-2)=(-2)\frac{-1}{2}x$

The right side cancels:

$-4=x\\$

Flip:

$x=-4$

So, x is -4.

Case II:

We have:

$1=x$

Flip:

$x=1$

This is the solution for our second case.

So, we have:

$x_1=-4\text{ or } x_2=1$

Now, can check to see if we have to to remove solution(s) that don't work.

Note that x=-4 is the solution to our first equation.

The first equation is defined only if x is less than -2.

-4 is less than -2. So, x=-4 is indeed a solution.

x=1 is the solution to our second equation.

The second equation is defined only if x is greater than or equal to -2.

1 is greater than or equal to -2. So, x=1 is also a solution.

Therefore, our two solutions are:

$x_1=-4\text{ or } x_2=1$

Out of our answer choices, we can pick D.

And we're done!

7 0

3 years ago

I just need to know what the answer is pls help!! ty!!

zhannawk [14.2K]

Answer:

Tangent is the answer.

Hope it helps!!!

4 0

2 years ago

Solve for b help please

aliya0001 [1]

Answer:

-12=-4/3b

-12x4/3=b

-16=b

b=-16

4 0

3 years ago