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STatiana [176]
3 years ago
15

NOV 06, 2:1

Mathematics
2 answers:
Lelu [443]3 years ago
8 0

Answer: 5

Step-by-step explanation:

Alex3 years ago
5 0

Answer: 6

Step-by-step explanation:

thank you to the user above for the comment i just entered it and 6 is correct in delta math

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CAN SOMEONE PLEASE HELP ME SOLVE THESE.<br> ik it’s a lot but i really need some help <br> thank you
Nutka1998 [239]
A 3x+3c
B 9x^2+12x
C -4ab+24a
D 3x-6
E 3x+3
F (x+1)(2x+3)
G x^2+x-6
H 6x^2-31x+18
I 6x-8y+11
J 2x^3+11x^2+17x+6

M=12

40

44

20

250/11

Last one is 33
6 0
3 years ago
Read 2 more answers
Whats the answer?<br><br> 12m +5 =17
Serga [27]

Answer:

m=1

Step-by-step explanation:

12m+5=17

       -5  -5

12m=12

m=1

3 0
3 years ago
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4^2 + 8 *2 the * stands for divide Answer choices A 12 B20 C8 D 16
irina1246 [14]
The answer would be B.20
5 0
3 years ago
Read 2 more answers
Need help explain to me
Natali [406]

9514 1404 393

Answer:

  A) (20 miles)/(1 gallon) = 20 miles per gallon

  B) 20/1 = 20

Step-by-step explanation:

After you read the problem statement and identify the questions being asked, it is a good idea to look carefully at the given information. Graphs A and B are identical in every way.

The vertical axis is labeled "y" and "Distance (miles)". The horizontal axis is labeled "x" and "Gallons". The graph starts at (0 gallons, 0 miles) and goes through points on the grid that are 2 squares up for each 1 square to the right. Each square up represents 10 miles. Each square to the right represents 1 gallon.

__

A) Pick two points on the graph. It is usually convenient to choose points where the graph crosses grid intersections. It is often convenient to choose one of them as (0, 0) if that point is on the graph (it is). I expect it to be convenient to choose the second point as (1 gallon, 20 miles).

The change in <em>distance</em> between the point (0 gallons, 0 miles) and (1 gallon, 20 miles) is (20 miles) - (0 miles) = 20 miles.

The change in <em>gallons</em> between the point (0 gallons, 0 miles) and (1 gallon, 20 miles) is (1 gallon) - (0 gallons) = 1 gallon.

The ratio of these changes is (20 miles)/(1 gallon) = 20 miles per gallon.

__

B) We can use the same two points. Here, we basically ignore the units.

Change in y = 20-0 = 20.

Change in x = 1 -0 = 1.

Slope = 20/1 = 20.

_____

<em>Additional comment</em>

For many problems, I find it convenient to keep the units with the numbers. Making sure the units work out properly is called "units analysis." Doing that can save you from a number of mistakes where units are involved.

Units can be treated just like a variable--multiplied, divided, raised to a power, cancelled from fractions. And, like with variables, terms can only be added or subtracted if they have the same units.

Here, we have ...

  \dfrac{\text{change in distance}}{\text{change in gallons}}=\dfrac{20\text{ miles}}{1\text{ gallon}}=\dfrac{20}{1}\times\dfrac{\text{miles}}{\text{gallon}}=20\text{ miles per gallon}

Note that "divided by" and "per" mean essentially the same thing in this context.

As you can see from the work done with Graph A, the slope of the line has units that are the ratio of the units of the y-axis to the units of the x-axis. (miles/gallon) Even though in Graph B, we write the slope as 20 without any units, it will only make any sense to use that number where units of miles/gallon make sense.

7 0
3 years ago
Can someone explain?
makkiz [27]

The correct statement regarding the quadratic function is:

K. I, II and III.

<h3>What is a quadratic function?</h3>

A quadratic function is given according to the following rule:

y = ax^2 + bx + c

If a > 0, it has a maximum value, and if a < 0, it has a minimum value.

The extreme value is (x_v,y_v), in which:

  • x_v = -\frac{b}{2a}
  • y_v = -\frac{\Delta}{4a}
  • \Delta = b^2 - 4ac

The solutions are:

  • x_1 = \frac{-b + \sqrt{\Delta}}{2a}
  • x_2 = \frac{-b - \sqrt{\Delta}}{2a}

In this problem, we have a function h(t). Changing the coefficient c, the h-intercept h(0) changes. Looking at the formulas in the bullet point, the value of \Delta changes, meaning that both the maximum value y_v and the t-intercepts t_1 and t_2 will change, so option K is correct.

More can be learned about quadratic functions at brainly.com/question/24737967

#SPJ1

7 0
2 years ago
Read 2 more answers
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