Answer:
782.290 MJ
Explanation:
Given Data:
number of poles ( p ) = 2-pole
Frequency ( f ) = 50 Hz
voltage ( v ) = 20 kV
power = 120 MVA
power factor (cos ∅ ) = 0.95
moment of inertia ( J ) = 11000 kg*m^2
First we calculate the value of
Ns = ( 120 * f ) / p
= ( 120 * 50 ) / 2 = 3000 rpm
Ws = ( 2Ns ) / f
= (2*3000 ) / 50 = 377.14 rad/sec
determine the kinetic energy of the machine
K.E =
= 1/2 * 11000 * ( 377.14 ) ^2
= 5500 * 142234.58 = 782.290 MJ
Answer:
a. 2x/3
b. 8
Explanation:
fundamental period can be defined to mean that at after every period of 2π radians or 360° the value of graph is repeated. For such functions the fundamental period is the period after which they repeat themselves.
It van also be looked as The fundamental period of cos(θ) is 2π. That is (for example) cos(0) to cos(2π) represents one full period.
Please see attachment for the step by step solution.
Solution:
Given that :
Volume flow is,
So,
Therefore, the equation of a single straight vessel is given by
......................(i)
So there are 100 similar parallel pipes of the same cross section. Therefore, the equation for the area is
or
Now for parallel pipes
...........(ii)
Solving the equations (i) and (ii),
Therefore,
or
Thus the answer is option A). 10