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Mariana [72]
3 years ago
15

I WILL GIVE BRAINLIEST PLEASE!!! A cereal company is having a special promotion. Every 4 out of 65 boxes contains a coupon for h

alf off your next box of cereal. Suppose 455 boxes of the cereal are delivered to a grocery store. How many of them can be expected to contain one of the coupons? Set up and solve a proportion to solve the problem. Show your work. (Please help me.)
Mathematics
1 answer:
ss7ja [257]3 years ago
4 0

Answer:

28

Step-by-step explanation:

4/65 then ?/455

divide 455 by 65 to get 7

4/65=4x7/65x7(455)

4/65=28/455

therefore there are 28 boxes with the coupon out 455

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I really need help! If you could
sp2606 [1]

Answer:

I'm not 100% on this but I believe it is 68° as well

I hope this is good enough:

6 0
3 years ago
If AABC = ADEC,<br> LC = 55°, ZD = 65°, and ZB = 2x<br> D<br> С<br> В B.<br> x = [?]
elena55 [62]

Answer:

x = 30

Step-by-step explanation:

65 + 55 = 120

angle B must equal 60

angle B is labeled as 2x

set up equation to solve for 'x':  2x = 60

                                                     x = 30

add up all angles to make sure you get 180 degrees

6 0
3 years ago
Six measurements were made of the magnesium ion concentration (in parts per million, or ppm) in a city's municipal water supply,
myrzilka [38]

Answer:

163.83-4.03\frac{20.094}{\sqrt{6}}=130.77    

163.83+4.03\frac{20.094}{\sqrt{6}}=196.89    

So on this case the 99% confidence interval would be given by (130.77;196.89)    

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Data: 175 177 175 180 138 138

We can calculate the mean and the deviation from these data with the following formulas:

\bar X= \frac{\sum_{i=1}^n x_i}{n}

s=\sqrt{\frac{\sum_{i=1}^n (x_i -\bar X)^2}{n-1}}

\bar X=163.83 represent the sample mean for the sample  

\mu population mean (variable of interest)

s=20.093 represent the sample standard deviation

n=6 represent the sample size  

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n-1=6-1=5

Since the Confidence is 0.99 or 99%, the value of \alpha=0.01 and \alpha/2 =0.005, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.005,5)".And we see that t_{\alpha/2}=4.03

Now we have everything in order to replace into formula (1):

163.83-4.03\frac{20.094}{\sqrt{6}}=130.77    

163.83+4.03\frac{20.094}{\sqrt{6}}=196.89    

So on this case the 99% confidence interval would be given by (130.77;196.89)    

7 0
3 years ago
Find each unknown number. a. 12 is 150% of what number? b. 5 is 50% of what number? c. 10% of what number is 300? d. 5% of what
siniylev [52]
Your answer would be c sorry if im wrong
7 0
3 years ago
Explain the graphing directions for the rules given below (x, y) = (x + 6, y – 3)
zaharov [31]
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Multiply the exponents in
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6 0
3 years ago
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