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devlian [24]
2 years ago
9

Regina eats a piece of fruit from a basket of apples, bananas, pears, and melons. Later her brother eats a piece of fruit from t

he basket. Do these represent independent or dependent events? Explain your answer.
Mathematics
1 answer:
Marta_Voda [28]2 years ago
6 0
These represent independent events because they are all equally distributed throughout this process theoretically proving that they are independent
You might be interested in
soymeal is 14 percent protein cornmeal is 7 percent protein how many pounds of each should be mixed together in order to get 280
erma4kov [3.2K]
Let the weight of soymeal be s, and let the weight of cornmeal be c.
You need a total of 280 lb, so that gives us one equation.

s + c = 280

Now we use the protein to write another equation.
The protein in s lb of soymeal is 0.14s.
The protein in c lb of cornmeal is 0.07c.
The protein in 280 lb of 0.09% protein mix is 0.09(280).
This gives us a second equation.

0.14s + 0.07c = 0.09(280)

Now we solve the two equations as a system of equations.

s + c = 280
0.14s + 0.07c = 0.09(280)

Solve the first equation for s and plug in tot eh second equation.

s = 280 - c

0.14(280 - c) + 0.07c = 25.2

39.2 - 0.14c + 0.07c = 25.2

-0.07c = -14

c = 200

Now we substitute c = 200 in the first equation to find s.

s + 200 = 280

s = 80

Answer: 200 lb of soymeal and 80 lb of cornmeal
6 0
3 years ago
Aaron drew the figure below for a school art project. What is the total area of the figure. Use the drop down menus to complete
Feliz [49]

Answer:

The trapezoid has a height of 3 inches, a shorter base measuring 2.75 inches, and a longer base measuring 4.25 inches. The total area of the entire figure is 33 square inches.

Step-by-step explanation:

I took the iready diagnostic :)

6 0
2 years ago
Read 2 more answers
Evaluate 5a-2b if a=3, and b=2
Anna71 [15]

Answer:

11

Step-by-step explanation:

4 0
3 years ago
B. 40 is 160% of what number?
Anton [14]

Answer:

25

Step-by-step explanation:

the question basically translates to

160% x n =40  

a little trick with percents I use is that the word "of" always means multiplication.

n=40/160%=25

6 0
2 years ago
A manufacturer uses production method to produce steel rods. A random sample of 17 steel rods resulted in lengths with a standar
Arisa [49]

Answer:

\chi^2 =\frac{17-1}{12.15} 22.09 =15.87

Traditional method

We can find a critical value in the chi square distribution with df =16 who accumulates \alpha/2 =0.05 of the area on each tail and we got:

\chi^2_{crit}= 7.962

\chi^2_{crit}=26.296

Since the calculated value is between the two critical values we don't have enough evidence to conclude that the true deviation is NOT significantly different from 3.5 cm

Confidence level method

We can find the p value like this

p_v =2*P(\chi^2 >15.87)=0.92

Since the p value is higher then the significance level we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviation is NOT significantly different from 3.5 cm

Step-by-step explanation:

Data provided

n=17 represent the sample selected

\alpha=0.1 represent the significance

s^2 =4.7^2 =22.09 represent the sample variance

\sigma^2_0 =3.5^2 =12.15 represent the value to check

Null and alternative hypothesis

We want to verify if the new production method has lengths with a standard deviation different from 3.5 cm, so the system of hypothesis would be:

Null Hypothesis: \sigma^2 = 12.15

Alternative hypothesis: \sigma^2 \neq 12.15

The statistic for this case is given by:

\chi^2 =\frac{n-1}{\sigma^2_0} s^2

The degrees of freedom are:

df =n-1= 17-1=16

\chi^2 =\frac{17-1}{12.15} 22.09 =15.87

Traditional method

We can find a critical value in the chi square distribution with df =16 who accumulates \alpha/2 =0.05 of the area on each tail and we got:

\chi^2_{crit}= 7.962

\chi^2_{crit}=26.296

Since the calculated value is between the two critical values we don't have enough evidence to conclude that the true deviation is significantly different from 3.5 cm

Confidence level method

We can find the p value like this

p_v =2*P(\chi^2 >15.87)=0.92

Since the p value is higher then the significance level we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviation is significantly different from 3.5 cm

7 0
3 years ago
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