Answer:
Assuming steady state condition the temperature distribution is calculated as expressed in the attached solution below
Explanation:
Given data :
thickness : L , inner surface (x) : 0, uniform flux : q"o
fraction : β
volumetric heat generation : q˙(x)=(1−β)q''oα^e−αx
determine the temperature distribution in the quartz
attached below is the detailed solution
Answer:
modify temperature is lower than by the 0.196 %
Explanation:
given data
D = 250 mm
d = 0.1 mm
v = 0.5 m/s
V = 50 m/s
D = 150 mm
d = 0.1 mm
v = 0.3 m/s
V = 25 m/s
solution
first we get here initial coating condition for temperature change ΔT is
ΔT = A \times D^{1/4} \times d^{3/4}\times \frac{V}{v}^{1/2} ...............1
put here value for both condition
ΔT = A \times 250^{1/4} \times 0.1^{3/4}\times \frac{50}{0.5}^{1/2}
ΔT = 7.07 A ......................2
and
ΔT = A \times 150^{1/4} \times 0.1^{3/4}\times \frac{25}{0.3}^{1/2}
ΔT = 5.68 A .......................3
so here percentage change is
percentage change =
percentage change = - 0.196
so that modify temperature is lower than by the 0.196 %
Answer:
Vector C = 1.334i + 8.671j + 2k or 1.334x + 8.671y + 2z
Explanation:
The concept applied to solve the question is cross product of vector, AXB since vector C is perpendicular to vector A and B and this is solved by applying the 3X3 determinant method.
A detailed step by step explanation is attached below.