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3 years ago

Air-breathing cold-blooded animals?

Engineering

1 answer:

ivanzaharov [21]3 years ago

5 0

Answer:

Fish breathe through gills, and live in water; most are cold-blooded and lay eggs (although sharks give birth to live young). ... Reptiles are cold-blooded and breathe with lungs. They have scales, and most lay eggs. Reptiles include snakes, turtles and tortoises, crocodiles and alligators, and lizards

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Ainat [17]

Answer:

meepus weepus

Explanation:

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3 years ago

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A horizontal curve on a two-lane road is designed with a 2,300-ft radius, 12-ft lanes, and a 65-mph design speed. Determine the

Ierofanga [76]

Answer:

distance = 22.57 ft

superelevation rate = 2%

Explanation:

given data

radius = 2,300-ft

lanes width = 12-ft

no of lane = 2

design speed = 65-mph

solution

we get here sufficient sight distance SSD that is express as

SSD = 1.47 ut + $\frac{u^2}{30(\frac{a}{g}\pm G)}$ ..............1

here u is speed and t is reaction time i.e 2.5 second and a is here deceleration rate i.e 11.2 ft/s² and g is gravitational force i.e 32.2 ft/s² and G is gradient i.e 0 here

so put here value and we get

SSD = 1.47 × 65 ×2.5 + $\frac{65^2}{30(\frac{11.2}{32.2}\pm 0)}$

solve it we get

SSD = 644 ft

so here minimum distance clear from the inside edge of the inside lane is

Ms = Rv ( 1 - $cos (\frac{28.65 SSD}{Rv})$ ) .....................2

here Rv is = R - one lane width

Rv = 2300 - 6 = 2294 ft

put value in equation 2 we get

Ms = 2294 ( 1 - $cos (\frac{28.65 \times 664}{2294})$ )

solve it we get

Ms = 22.57 ft

and

superelevation rate for the curve will be here as

R = $\frac{u^2}{15(e+f)}$ ..................3

here f is coefficient of friction that is 0.10

put here value and we get e

2300 = $\frac{65^2}{15(e+0.10)}$

solve it we get

e = 2%

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3 years ago

Rolling and Shearing are the types of a)-Bulk Deformation Process b)- Sheet Metal Process c)- Machining Process d)- Both a &

Margarita [4]

Answer:

a)Bulk deformation process

Explanation:

<u>Rolling</u>

Rolling is a metal forming process.In rolling work piece passes through two moving rollers and get compressed.in rolling thickness of work piece will reduces and length of work piece will increase for maintaining the constant area.Due to compression bulk deformation takes place.

<u>Shearing</u>

In shearing one surface slides on another surface and deformation take place.shearing is a machining process.This is also a bilk motion deformation process.

So from above we can say that option a is right.

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3 years ago

Thermal energy is...

Yuki888 [10]

B because thermal has to do with temperature and it’s the amount of kinetic and potential energy in and object

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3 years ago

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Consider a solid circular shaft subjected to bending and torsion so that the state of stress of interest involves only a normal

Alex17521 [72]

Answer: