Answer:
The displacement from t = 0 to t = 10 s, is -880 m
Distance is 912 m
Explanation:
. . . . . . . . . . A
integrate above equation we get
from information given in the question we have
t = 1 s, s = -10 m
so distance s will be
-10 = 12 - 1 + C,
C = -21
we know that acceleration is given as
[FROM EQUATION A]
Acceleration at t = 4 s, a(4) = -24 m/s^2
for the displacement from t = 0 to t = 10 s,
the distance the particle travels during this time period:
let v = 0,
t = 2 s
Distance
Answer:
Hello your question is incomplete attached below is the complete question
answer:
Considering Laminar flow
Q ( heat ) will be independent of diameter
Considering Turbulent flow
The heat transfer will increase with decreasing "dia" for the turbulent
heat transfer = f(d^-0.8 )
Explanation:
attached below is the detailed solution
Considering Laminar flow
Q ( heat ) will be independent of diameter
Considering Turbulent flow
The heat transfer will increase with decreasing "dia" for the turbulent
heat transfer = f(d^-0.8 )
