Answer:
1) 1.4(D + F)
2) 1.2(D + F + T) + 1.6(L + H) + 0.5(Lr or S or R)
3) 1.2D + 1.6(Lr or S or R) + ((0.5 or 1.0)*L or 0.8W)
4) 1.2D + 1.6W + (0.5 or 1.0)*L + 0.5(Lr or S or R)
5) 1.2D + 1.0E + (0.5 or 1.0)*L + 0.2S
6) 0.9D + 1.6W + 1.6H
7) 0.9D + 1.0E + 1.6H
Explanation:
Load and Resistance Factor Design
there are 7 basic load combination of LRFD that is
1) 1.4(D + F)
2) 1.2(D + F + T) + 1.6(L + H) + 0.5(Lr or S or R)
3) 1.2D + 1.6(Lr or S or R) + ((0.5 or 1.0)*L or 0.8W)
4) 1.2D + 1.6W + (0.5 or 1.0)*L + 0.5(Lr or S or R)
5) 1.2D + 1.0E + (0.5 or 1.0)*L + 0.2S
6) 0.9D + 1.6W + 1.6H
7) 0.9D + 1.0E + 1.6H
and
here load factor for L given ( * ) mean it is permitted = 0.5 for occupancies when live load is less than or equal to 100 psf
here
D is dead load and L is live load
E is earth quake load and S is snow load
W is wind load and R is rain load
Lr is roof live load
Answer:
hope this helps
Explanation:
answers:
1. Chemical engineering is most difficult because it's a mix of physics, chemistry and math
2. Stoichiometry is so important because it shows how materials react, interact and play off each other
3. Yes I think consumers would notice if process control standards were not met. for example medicines, when people take Tylenol or cold pills, if the amount of time it took to kick it becomes longer, people will become aware that the product is not consistent and reliable.
4. i have no idea sorry :(
5. This is explaining how there are rules and regulations to make the workplace safe. it can be accomplished by following those rules and regulations
Answer:
7.7 kN
Explanation:
The capacity of a material having a crack to withstand fracture is referred to as fracture toughness.
It can be expressed by using the formula:
where;
fracture toughness K = 137 MPa
geometry factor Y = 1
applied stress 
= ???
crack length a = 2mm = 0.002
∴
Now, the tensile impact obtained is:
P = A × σ
P = 1728.289 × 4.5
P = 7777.30 N
P = 7.7 kN
Answer:
The work of the cycle.
Explanation:
The area enclosed by the cycle of the Pressure-Volume diagram of a Carnot engine represents the net work performed by the cycle.
The expansions yield work, and this is represented by the area under the curve all the way to the p=0 line. But the compressions consume work (or add negative work) and this is substracted fro the total work. Therefore the areas under the compressions are eliminated and you are left with only the enclosed area.
