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Westkost [7]
3 years ago
15

Consider a solid circular shaft subjected to bending and torsion so that the state of stress of interest involves only a normal

stress and a shear stress, with all other stress components being zero.
(a) Determine the safety factor against yielding as a function of the yield strength of the ductile material and the applied stresses.
(b) Use the results of (a) to develop a design equation for the shaft giving diameter d as a function of yield strength, safety factor, bending moment M, and torque T.

Engineering
1 answer:
Alex17521 [72]3 years ago
7 0

Answer:

The detailed explanation of answer is given in attached file.

Explanation:

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Explanation:

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A hawser is wrapped two full turns around a bollard. By exerting an 80-lb force on the free end of the hawser, a dockworker can
Brut [27]

Answer:

μ=0.329, 2.671 turns.

Explanation:

(a)   ln(T2/T1)=μβ         β=angle of contact in radians

take T2 as greater tension value and T1 smaller, otherwise the friction would be opposite.

T2=5000 lb and T1=80 lb

we have two full turns which makes total angle of contact=4π  radians

μ=ln(T2/T1)/β=(ln(5000/80))/4π  

μ=0.329

(b) using the same relation as above we will now compute the angle of contact.

take greater tension as T2 and smaller as T1.

T2=20000 lb     T1=80 lb   μ=0.329

β=ln(20000/80)/0.329=16.7825 radians

divide the angle of contact by 2π to obtain number of turns.

16.7825/2π =2.671 turns

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Answer:

Here are 2 sense i cant find 4

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