Shaded raea = area of circle - area of hexagon
area of circle = pi r^2 = 36pi
area of hexagon = 3 sqrt3 * a^2 / 2 where a = length of each side
To find a:-
consider the triangle with vertex angle = 60 and 2 sides enclosed by 2 sides of length 6 this is an equilateral triangle so a = 6
so, area of hexagon = 3*sqrt3* 6^2 / 2 = 93.531 cm^2
Area of shaded region = 36 pi - 93.531 cm^2
= 19.57 cm^2
the domain of f(x)= x2 +1 is limited to {0,1,2,3)
the maximum value will be at the maximum value of x which is at x = 3
So, the maximum value of the range will be = 3^2 + 1 = 9 + 1 = 10
Answer:
log(0.0003) = -3.5229
Step-by-step explanation:
The rules of logarithms tell you ...
log(ab) = log(a) +log(b)
<h3>Application</h3>
log(0.0003) = log(3×10^-4) = log(3) +log(10^-4)
= log(3) -4 = 0.4771 -4
log(0.0003) = -3.5229
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<em>Additional comment</em>
If you do much work with logarithms, you find that negative logarithms are generally expressed using a positive mantissa with a negative add-on. Often, that negative add-on is -9, so this would be ...
5.4771-9
This helps when taking antilogs, as you look up 0.4771 in the table to see that the multiplier is 3.
If you were to look up 0.5229, you would find 3.333, meaning the multiplier is 1/3.333 and the antilog of -3.5229 is (10^-3)/3.333. This may not be a convenient value to work with.
Answer:
Step-by-step explanation:
1) in order to graph the required direct line it needed two points:
2) one of these two points is Y-intercept. According to the condition it is (0;1);
3) in order to find the second point, it is enough to apply the given slope: to start in point (0;1), then to move to the left direction (-5 units, move no. 1), then to move up (+7 units, move no. 2);
4) to graph the line between two points (red line); y= -7/5x +1.
All the details are in the attachment.