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3 years ago

PLEASE HELP!! Its easy!!!

Engineering

2 answers:

tankabanditka [31]3 years ago

5 0

Answer: give me brainliest, fellow hamster friend

Explanation:

Rina8888 [55]3 years ago

4 0

Answer:

C is tire

F is cassette

D is hub

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What is the work required to deflect a linear spring (k=32 kN/m) by 120 cm?

Anit [1.1K]

Answer:

the work done by the linear spring will be equal to 23.04 k J

Explanation:

given,

k = 32 k N /m

deflected spring = 120 cm

= 1.2 m

work done by spring can be calculate as

= $\dfrac{1}{2}kx^2$

= $\dfrac{1}{2}\times 32 \times 1.2^2$

= 23.04 k J

hence, the work done by the linear spring will be equal to 23.04 k J

6 0

3 years ago

Write a single statement to print: user_word,user_number. Note that there is no space between the comma and user_number. Sample

kykrilka [37]

Answer:

cout<<"''<<user_word<<"' "<<user_number;

Explanation:

The above question was answered using C++ programming language.

The keyword cout represents print and it carries out print operation only.

It prints all variable in front of it.

Assume the values of user_word and user_number to be Charles and 20, respectively.

The output of the above instruction would be

'Charles' 20 just as it is in the sample output in the question.

In java programming language, it is

System.out.print("'"+user_word+"' "+user_number);

In Qbasic, it is

PRINT "'"+user_word+"' "+ user_number

8 0

3 years ago

What is an example of a product made of textile?

Otrada [13]

$beach \: towel \\ \\ hope \: it \: helps$

4 0

2 years ago

Electricity is the flow of electrons from a negatively charged

TiliK225 [7]

Yes.

electric current refers to directional negative-to-positive electrons from one atom to the next. Liquid conductors and gas conductors, electric current refers to electrons and protons flow in the opposite direction.

6 0

1 year ago

Oil with a kinematic viscosity of 4 10 6 m2 /s fl ows through a smooth pipe 12 cm in diameter at 2.3 m/s. What velocity should w

Setler79 [48]

Answer:

Velocity of 5 cm diameter pipe is 1.38 m/s

Explanation:

Use following equation of Relation between the Reynolds numbers of both pipes

$Re_{5}$ = $Re_{12}$

$\sqrt{\frac{V_{5}XD_{5} }{v_{5}}}$ = $\sqrt{\frac{V_{12}XD_{12} }{v_{12}}}$

$Re_{5}$ = Reynold number of water pipe

$Re_{12}$ = Reynold number of oil pipe

$V_{5}$ = Velocity of water 5 diameter pipe = ?

$V_{12}$ = Velocity of oil 12 diameter pipe = 2.30

$v_{5}$ = Kinetic Viscosity of water = 1 x $10^{-6}$ $m^{2}$ /s

$v_{12}$ = Kinetic Viscosity of oil = 4 x $10^{-6}$ $m^{2}$ /s

$D_{5}$ = Diameter of pipe used for water = 0.05 m

$D_{12}$ = Diameter of pipe used for oil = 0.12 m

Use the formula

$\sqrt{\frac{V_{5}XD_{5} }{v_{5}}}$ = $\sqrt{\frac{V_{12}XD_{12} }{v_{12}}}$

By Removing square rots on both sides

${\frac{V_{5}XD_{5} }{v_{5}}}$ = ${\frac{V_{12}XD_{12} }{v_{12}}}$

${V_{5}$ = ${\frac{V_{12}XD_{12} }{v_{12}XD_{5}\\}}$ x $v_{5}$

${V_{5}$ = [ (0.23 x 0.12m ) / (4 x $10^{-6}$ $m^{2}$ /s) x 0.05 ] 1 x $10^{-6}$ $m^{2}$ /s

${V_{5}$ = 1.38 m/s

4 0

3 years ago