Here is the factored polynomial
(x^2+9)(x^2-3x-9)=0
Answer: I-
ok
Step-by-step explanation:
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charlidamelio
The graph is touching the x-axis at x= 2 and is turning away.
When a graph exhibit such a behavior at a root, we say that the multiplicity of the root is 2. So the roots of the polynomial are x = 2 and x = 2. The factors of the polynomial are (x - 2) and (x - 2)
The polynomial thus can be written as product of its factors as (x-2)(x-2)
So the correct answer to this question is option B
Answer:
2/3
Step-by-step explanation:
If the line is perpendicular, multiply the slope by -1 to find the answer
Answer:
3 x^2 +12x-9
Step-by-step explanation:
5x^2 - (2x-3)^2
We need to FOIL the second term
(2x-3)^2 = (2x-3) (2x-3) = 4x^2 -6x-6x+9 = 4x^2 -12x+9
Replacing it in to the original equation
5x^2 - (4x^2 -12x+9)
Distribute the minus sign
5x^2 - 4x^2 +12x-9
Combine like terms
x^2 +12x-9
