These two triangles are congruent.
2 answers:
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Try this:
Given:
![\left \{ {{x-y=1} \ [1] \atop {x+y=3} \ [2]} \right.](https://tex.z-dn.net/?f=%20%5Cleft%20%5C%7B%20%7B%7Bx-y%3D1%7D%20%5C%20%5B1%5D%20%5Catop%20%7Bx%2By%3D3%7D%20%5C%20%5B2%5D%7D%20%5Cright.%20)
1) [1]+[2]: 2x=2 ⇒ x=2
2) [2]-[1]: 2y=1 ⇒ y=1.
3) answer: (2;1)
Given:
1) [1]+[2]: 2x=2 ⇒ x=2
2) [2]-[1]: 2y=1 ⇒ y=1.
3) answer: (2;1)
Something that you should remember is that the sum of the angles of a triangle add up to 180°.
Since we are given 100° and that the other two angles are equal, we can set up an equation like this:
, where x is the 2 angles.
Doing the math, the measure of each unknown angles is 40°.