If A and B are equal:
Matrix A must be a diagonal matrix: FALSE.
We only know that A and B are equal, so they can both be non-diagonal matrices. Here's a counterexample:
![A=B=\left[\begin{array}{cc}1&2\\4&5\\7&8\end{array}\right]](https://tex.z-dn.net/?f=A%3DB%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D1%262%5C%5C4%265%5C%5C7%268%5Cend%7Barray%7D%5Cright%5D)
Both matrices must be square: FALSE.
We only know that A and B are equal, so they can both be non-square matrices. The previous counterexample still works
Both matrices must be the same size: TRUE
If A and B are equal, they are literally the same matrix. So, in particular, they also share the size.
For any value of i, j; aij = bij: TRUE
Assuming that there was a small typo in the question, this is also true: two matrices are equal if the correspondent entries are the same.
It's not necessary that either one represents a proportional
relationship. But if either one does, then the other one doesn't.
They can't both represent such a relationship.
The graph of a proportional relationship must go through
the origin. If one of a pair of parallel lines goes through
the origin, then the other one doesn't. (If two parallel lines
both went through the origin, then they would both be the
same line.)
Answer:
for the third question y = 5, x = 3
Step-by-step explanation:
Answer:
113.04
Step-by-step explanation:
the equation for the area of a circle is pie times radius squared
Answer:
12 Newtons
Step-by-step explanation:
We can use Newton’s Second Law to find the mass first.
F = ma
9 = 3m
mass = 3
Substitute this into the second equation.
F = ma
F = 3(4)
F = 12N
Hope this helps! :D
