Answer:
a. x = + 2
b. x = + 3
c. x = + 2
d. x = + 3
Explanation:
The oxidation number is a formal charge assigned to an atom present in a molecule or formula unit or ion based on some arbitrary rules.
a.
<u>Hg</u>O
The oxidation number of Hg in HgO is:
x + (-2) = 0
x = +2
b.
<u>Al₄</u>C₃
The oxidation number of Al in Al<u>₄</u>C₃ is:
4x +(3 × -4) = 0
4x - 12 = 0
4x = +12
x = 12/4
x = +3
c. CrF₂
x + ( 2 × - 1) = 0
x - 2 = 0
x = + 2
d. Fe₂S₃
2x + ( 3 × - 2) = 0
2x + (-6) = 0
2x = 6
x = 6/2
x = +3
<span>the answer is 1 the 4s1 electron........................
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Mass, if you know what element you are working with.
You can simply subtract the atomic number from the mass number in order to find the number of neutrons.
