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saw5 [17]
3 years ago
10

What is the area of S-t graph​

Physics
1 answer:
lara31 [8.8K]3 years ago
4 0

Answer:

Area under DT graph

Important: The area between a velocity-time graph and the `time' axis gives the displacement of the object. The slope is the same all the way from A to C, so the cyclist's velocity is constant over the entire displacement he travels. In figure 5.1 are examples of the displacement-time graphs you will encounter.

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I have an object that I want to know when it was made. I calculate that the object contains 0.12g of Iodine-131 but started with
Sav [38]

Answer: 71.72 days

Explanation:

This problem can be solved using the <u>Radioactive Half Life Formula: </u>

A=A_{o}.2^{\frac{-t}{h}} (1)  

Where:  

A=0.12 g is the final amount of Iodine-131

A_{o}=60 g is the initial amount of Iodine-131

t is the time elapsed  

h=8 days is the half life of Iodine-131

Knowing this, let's substitute the values and find t from (1):

0.12 g=(60 g)2^{\frac{-t}{8 days}} (2)  

\frac{0.12 g}{60g}=2^{\frac{-t}{8 days}} (3)  

Applying natural logarithm in both sides:

ln(\frac{0.12 g}{60g})=ln(2^{\frac{-t}{8 days}}) (4)  

-6.21=-\frac{t}{8 days}ln(2) (5)

Finding t:

t=71.72 days

7 0
4 years ago
Alex is asked to move two boxes of books in contact with each other and resting on a rough floor. He decides to move them at the
Over [174]

Answer:

Part a)

a= 0.32 m/s^2

Part b)

F_c = 3.6 N

Part c)

F_c = 5.5 N

Explanation:

Part a)

As we know that the friction force on two boxes is given as

F_f = \mu m_a g + \mu m_b g

F_f = 0.02(10.6 + 7)9.81

F_f = 3.45 N

Now we know by Newton's II law

F_{net} = ma

so we have

F_p - F_f = (m_a + m_b) a

9.1 - 3.45 = (10.6 + 7) a

a = \frac{5.65}{17.6}

a= 0.32 m/s^2

Part b)

For block B we know that net force on it will push it forward with same acceleration so we have

F_c - F_f = m_b a

F_c = \mu m_b g + m_b a

F_c = 0.02(7)(9.8) + 7(0.32)

F_c = 3.6 N

Part c)

If Alex push from other side then also the acceleration will be same

So for box B we can say that Net force is given as

F_p - F_f - F_c = m_b a

9.1 - 0.02(7)(9.8) - F_c = 7(0.32)

F_c = 9.1 - 0.02 (7)(9.8) - 7(0.32)

F_c = 5.5 N

3 0
3 years ago
An astronaut lands on an alien planet. He places a pendulum (L = 0.200 m) on the surface and sets it in simple harmonic motion,
grigory [225]
I think b or c sorry
3 0
3 years ago
How many swings would a 23 cm long pendulum make in 30 seconds?
iragen [17]

Is there any possible chance that at some point in your science
studies, sometime before you were given this question for your
homework, that maybe you might have encountered this formula
for the period of a simple pendulum ?

                   Period = (2 pi) √(length/gravity) .

If the length is 0.23 meter, and the
acceleration of gravity is 9.8 m/s²,
then the period is

                                 = (2 pi) √(0.23/9.8)

                                 =   0.963... second  (rounded)

That's how long it takes for a simple pendulum, 23cm long,
hanging on a massless string and not swinging too far to
the side, to complete one full swing left and right.

Now, if you can figure out how many periods of  0.963 second
there are in  30 seconds, you'll have your answer.  I'll leave
that part of it to you.

8 0
3 years ago
Jane described two substances which participate in photosynthesis. Substance A: Combines with water Substance B: Gaseous product
saul85 [17]
<span>I am pretty sure the correct answer is C.
It makes the most sense.
Please correct me if I'm wrong.</span>
5 0
3 years ago
Read 2 more answers
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