Answer:
option (a)
Explanation:
In an isothermal process, the temperature of the gas remains constant.
The internal energy of the gas is the function of change in temperature.
As the temperature is constant, so there is no change in the internal energy of the gas.
So, internal energy change is zero.
The <u>apparent magnitude</u> of a star refers to its brightness as seen from your eyes and <u>absolute magnitude</u> being the actual brightness of a star.
<h3>What is magnitude?</h3>
Magnitude can be defined as a unitless measure which is used to show the brightness of an object in comparison with the brightness of another object.
Basically, there are two types of magnitude and these include the following:
In conclusion, the <u>apparent magnitude</u> of a star refers to its brightness as seen from your eyes and <u>absolute magnitude</u> being the actual brightness of a star.
Read more on absolute magnitude here: brainly.com/question/1056710
#SPJ1
Answer:
Electric field, E = 40608.75 N/C
Explanation:
It is given that,
Mass of electrons, ![m=9.1\times 10^{-31}\ kg](https://tex.z-dn.net/?f=m%3D9.1%5Ctimes%2010%5E%7B-31%7D%5C%20kg)
Initial speed of electron, u = 0
Final speed of electrons, ![v=3\times 10^7\ m/s](https://tex.z-dn.net/?f=v%3D3%5Ctimes%2010%5E7%5C%20m%2Fs)
Distance traveled, s = 6.3 cm = 0.063 m
Firstly, we will find the acceleration of the electron using third equation of motion as :
![a=\dfrac{v^2-u^2}{2s}](https://tex.z-dn.net/?f=a%3D%5Cdfrac%7Bv%5E2-u%5E2%7D%7B2s%7D)
![a=\dfrac{(3\times 10^7)^2}{2\times 0.063}](https://tex.z-dn.net/?f=a%3D%5Cdfrac%7B%283%5Ctimes%2010%5E7%29%5E2%7D%7B2%5Ctimes%200.063%7D)
![a=7.14\times 10^{15}\ m/s^2](https://tex.z-dn.net/?f=a%3D7.14%5Ctimes%2010%5E%7B15%7D%5C%20m%2Fs%5E2)
Now we will find the electric field required in the tube as :
![ma=qE](https://tex.z-dn.net/?f=ma%3DqE)
![E=\dfrac{ma}{q}](https://tex.z-dn.net/?f=E%3D%5Cdfrac%7Bma%7D%7Bq%7D)
![E=\dfrac{9.1\times 10^{-31}\times 7.14\times 10^{15}}{1.6\times 10^{-19}}](https://tex.z-dn.net/?f=E%3D%5Cdfrac%7B9.1%5Ctimes%2010%5E%7B-31%7D%5Ctimes%207.14%5Ctimes%2010%5E%7B15%7D%7D%7B1.6%5Ctimes%2010%5E%7B-19%7D%7D)
E = 40608.75 N/C
So, the electric field required in the tube is 40608.75 N/C. Hence, this is the required solution.