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svp [43]
3 years ago
13

The energy source in photosynthesis is a. Light energy. C. Heat energy. B. Chemical energy. D. Kinetic energy. Please select the

best answer from the choices provided A B C D
Physics
1 answer:
stira [4]3 years ago
4 0

energy source in photosynthesis is light energy so, choice A is right answer

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Which of these is an example of a chemical change?
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1 - fireworks exploding
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You serve a volleyball with a mass of 0.77 kg. The ball leaves your hand with a velocity of
dimaraw [331]
<h2>Given :</h2>

  • mass (m) = 0.77 kg

  • velocity (v) = 2.33 m/s

<h2>Solution :</h2>

\boxed{ \mathrm{Kinetic  \: Energy =  \frac{1}{2} m {v}^{2} }}

  • \dfrac{1}{2}  \times 0.77 \times (2.33) {}^{2}

  • \dfrac{418.0253}{2}

  • 209.01265  \: \: joules

  • \mathrm{209.01  \: \: joules} \:  \:  \: (approx)

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\mathrm{ \#TeeNForeveR}

7 0
3 years ago
An electron moves through a uniform electric field E = (2.00î + 5.40ĵ) V/m and a uniform magnetic field B = 0.400k T. Determine
EleoNora [17]

Answer:a=1.75\times 10^{21}\left ( 2\hat{i}5.08\hat{j}\right )

Explanation:

Given

Electric Field \vec{E}=2\hat{i}+5.4\hat{j}

\vec{B}=0.4\hat{k}\ T

velocity \vec{v}=8\hat{i} m/s

mass of electron m=9.1\times 10^{-31} kg

Force on a charge Particle moving in Magnetic Field

F=e\left [ \vec{E}+\left ( \vec{v}\times \vec{B}\right )\right ]

a=\frac{e\left [ \vec{E}+\left ( \vec{v}\times \vec{B}\right )\right ]}{m}

a=\frac{1.6\times 10^{-19}\left [ 2\hat{i}+5.4\hat{j}+\left ( 8\hat{i}\times 0.4\hat{k}\right )\right ]}{9.1\times 10^{-31}}  

a=1.75\times 10^{21}\left ( 2\hat{i}+5.08\hat{j}\right )\ m/s^2

7 0
3 years ago
A roller coaster moving down a hill is an example of what kind of energy
GalinKa [24]
That would be kinetic energy
5 0
3 years ago
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A mass of 0.40 kg is suspended on a spring which then stretches 10 cm. The mass is then removed and a second mass is placed on t
Vanyuwa [196]

Answer:

 x' = 1.01 m

Explanation:

given,

mass suspended on the spring, m = 0.40 Kg

stretches to distance, x = 10 cm  = 0. 1 m

now,

we know

m g = k x

where k is spring constant

0.4 x 9.8 = k x 0.1

  k = 39.2 N/m

now, when second mass is attached to the spring work is equal to 20 J

work done by the spring is equal to

W = \dfrac{1}{2}kx'^2

20= \dfrac{1}{2}\times 39.2\times x'^2

 x'² = 1.0204

 x' = 1.01 m

hence, the spring is stretched to 1.01 m from the second mass.

 

7 0
3 years ago
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