Question

A bag contains 6 red marbles, 5 blue marbles and 8 green marbles. If three marbles are drawn out of the bag, what is the probability, to the nearest 10th of a percent, that all three marbles drawn will be green?​

Answer 1

Answer: 5.8%

Step-by-step explanation:

In this situation there is no replacement so we have to mulitply the probablilty of the first,second, and third marble being green. First marble has a 8/19 probablilty of being selected because 19 total marbles in the bag and 8 green marbles. the next marble will have a 7/18 probabililty because now only 18 marble are in the bag and we are assuming we selected a green marble on our first draw. Same thing with the last green marble it would be 6/17 because there would be 17 marbles in the bag and 6 green ones left assuming we got the first 2

so 8/19*7/18*6/17=

56/969=

0.05779

5.77%

5.8%