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Answer:
Empirical formula is C3H3O
Molecular formula C9H9O3
Explanation:
From the question given, we obtained the following data:
Carbon = 63.15%
Hydrogen = 5.30%
Oxygen = 31.55%
We can obtain the empirical and molecular formula by doing the following as illustrated in the attached file. Please see attachment for explanation.
<span>Ans : When looking at the second equation, we see it is double the first reaction and in the opposite direction.
First, change the direction of the first equation. When the direction of the reaction is changed, the sign on ΔH changes for the reaction
H​2O2(l) → H2O(l) + 1/2 O2(g); ΔH = -98.2 kJ
becomes
H2O(l) + 1/2 O2(g) → H2O2(l); ΔH = +98.2 kJ
Second, multiply this reaction by 2. When multiplying a reaction by a constant, the ΔH is multiplied by the same constant.
2 H2O(l) + O2(g) → 2 H2O2(l); ΔH = +196.4 kJ
ANSWER:
ΔH = +196.4 kJ for the reaction: 2 H2O(l) + O2(g) → 2 H2O2(l)</span>
