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Strike441 [17]
3 years ago
6

Opening a can of paint requires a screwdriver or other machine to pry open the lid. how does a screwdriver affect the force appl

ied to opening the lid
A. it increases the applied force and reduces its distance
B. it increases the applied force and changes its distance and direction
C. it changes the distance of the applied force
Chemistry
2 answers:
PtichkaEL [24]3 years ago
8 0

Answer:

It increases the applied force and changes its distance and direction

Explanation:

Opening a can of paint requires a screwdriver or other machine to pry open the lid. Screwdriver is type of simple machine.    

A screwdriver affect the force applied to opening the lid. Screwdriver is used to increase applied torque. It also changes the distance and the direction of the applied force.

So, the correct option is (b) " it increases the applied force and changes its distance and direction ".

joja [24]3 years ago
7 0
<span>Opening a can of paint requires a screwdriver or other machine to pry open the lid. The screwdriver affect the force applied to opening the lid.  The answer is :  </span><span>B.  It increases the applied force and changes its distance and direction.</span>
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Reactants :

I₂   ,   O₂

Products :

I₄O₉

hope this helps!

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Chlorine has seven electrons in its valence shell. It accepts an electron to complete its octet and becomes a chlorine ion (Cl-)
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pishuonlain [190]

<u>Answer:</u>

<u>For A:</u> The equation is _{92}^{238}\textrm{U}\rightarrow _{90}^{234}\textrm{Th}+_2^4\alpha

<u>For B:</u> The equation is _{94}^{239}\textrm{Pu}\rightarrow _{92}^{235}\textrm{U}+_2^4\alpha

<u>For C:</u> The equation is _{90}^{239}\textrm{Th}\rightarrow _{91}^{235}\textrm{Pa}+_{-1}^0\beta

<u>Explanation:</u>

Alpha decay process is the process in which nucleus of an atom disintegrates into two particles. The first one which is the alpha particle consists of two protons and two neutrons. This is also known as helium nucleus. The second particle is the daughter nuclei which is the original nucleus minus the alpha particle released.

_Z^A\textrm{X}\rightarrow _{Z-2}^{A-4}\textrm{Y}+_2^4\alpha

Beta decay process is defined as the process the neutrons get converted into an electron and a proton. The released electron is known as the beta particle. In this process, the atomic number of the daughter nuclei gets increased by a factor of 1 but the mass number remains the same.

_Z^A\textrm{X}\rightarrow _{Z+1}^A\textrm{Y}+_{-1}^0\beta

<u>For A:</u> Uranium-238 emits an alpha particle

The nuclear equation for this process follows:

_{92}^{238}\textrm{U}\rightarrow _{90}^{234}\textrm{Th}+_2^4\alpha

<u>For B:</u> Plutonium-239 emits an alpha particle

The nuclear equation for this process follows:

_{94}^{239}\textrm{Pu}\rightarrow _{92}^{235}\textrm{U}+_2^4\alpha

<u>For C:</u> Thorium-239 emits a beta particle

The nuclear equation for this process follows:

_{90}^{239}\textrm{Th}\rightarrow _{91}^{235}\textrm{Pa}+_{-1}^0\beta

6 0
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andriy [413]

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