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kipiarov [429]
4 years ago
13

A gas has a volume of 590 mL at a temperature of -55 C. What volume will the gas occupy at 30 C?

Chemistry
1 answer:
Vilka [71]4 years ago
8 0

Answer:750.550mL

Explanation:

V1/T1=v2/T2

V1=540mL

T1=-55°c to convert to Kelvin

273-55=218k

V2=?

T2=30°c to convert to Kelvin

273+30=303k

540/218=v2/303

Cross multiply

218v2=540×303

V2=540×303/218

V2=163620/218

V2=750.550mL

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How many Mg 2+ ions are present in 3.00 moles of MgCl2
Nostrana [21]
This is what I got hope this makes sense:There is 1 mol of Mg 2+ ions in one mole of MgCl2, we can get that from the formula.
Multiply 3.00 moles by 6.022x10^23 to get moles of MgCl2.
There are 6.022x10^23 ions in one mole of substance.
(3.00)(6.022x10^23)
=1.81x10^24 Mg 2+ ions
Hope it helps though
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3 years ago
7 Which of the following functional groups is present in an organic compound which gives bubbles on treatment with a saturated s
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Answer:

A. Carboxyl group

Explanation:

The carboxyl group is an organic functional group in chemistry that consists of a carbon atom double-bonded to an oxygen atom and singly linked to a hydroxyl group. Another way to think about it is as a carbonyl group (C=O) with an attached hydroxyl group (O-H).

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What type of energy must you add to a substance to make the particles of the substance
algol13

Answer: thermal  energy a}

Explanation:

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3 0
3 years ago
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Identify the type of chemical bond in a molecule reactant
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Draw the electron-dot (Lewis) structure of O2. You will see that there is a double bond, thus making the chemical bond a covalent bond since they have to share a pair of electrons in order to complete their octet.
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A gas mixture being used to simulate the atmosphere of another planet at 23°c consists of 337 mg of methane, 148 mg of argon, an
Karolina [17]

The total pressure of the mixture is 65.5 kPa.

According to Dalton's Law of Partial Pressure,

The partial pressure of gas = Mole fraction of gas × Total pressure

Total Pressure = Sum of all the gases partial pressures

The number of moles of methane is,

Moles \:  of \: methane  \: (16 g/mol) =  337 \: mg  \times  \frac{1 g}{1000 mg} \times  \frac{ 1 mol}{16 g }

= 0.021 mols

The moles of methane are 0.021 mols.

The number of moles of the argon,

Moles \:  of \: argon (40 g/mol) = 148 \:  mg  \times  \frac{  1 g}{1000 mg } \times  \frac{  1 mol}{40 g}

= 0.003 mols

The number of moles of argon is 0.003 mols.

The number of moles of nitrogen is,

Moles  \: of \: nitrogen (28 g/mol) = 296 \:  mg  \times  \frac{ 1 g}{1000 mg}  \times  \frac{  1 mol/}{28 g}

= 0.010 mols

The number of moles of nitrogen is 0.010 mols.

The total number of moles is,

= 0.021 + 0.003 + 0.010

= 0.034 mols

Mole \:  fraction =  \frac{ Moles \:  of \:  solute }{Total \:  number  \: of  \:  moles  \: of  \: soulte \:  and \:  solvent}

= \frac{  0.010 }{ 0.034}

= 0.29

0.29 \: P _{total} = 19 \:  kPa

P _{total} =  \frac{ 19  \: kPa }{0.29}

= 65.5 kPa

Therefore, the total pressure of the mixture is 65.5 kPa.

To know more about Dalton's law, refer to the below link:

brainly.com/question/14119417

#SPJ4

6 0
1 year ago
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