Answer:
Step-by-step explanation:
![the \: \sqrt[3]{121} \: is \: not \: a \: perfect \: cube \\ but \\ the \: \sqrt{121} = 11 \to \: is \: a \: perfect \: square \\](https://tex.z-dn.net/?f=the%20%5C%3A%20%20%5Csqrt%5B3%5D%7B121%7D%20%20%5C%3A%20is%20%5C%3A%20not%20%5C%3A%20a%20%5C%3A%20perfect%20%5C%3A%20cube%20%5C%5C%20but%20%5C%5C%20the%20%5C%3A%20%20%5Csqrt%7B121%7D%20%20%3D%2011%20%5Cto%20%5C%3A%20is%20%5C%3A%20a%20%5C%3A%20perfect%20%5C%3A%20square%20%5C%5C%20)
2x+3=7
2x+3-3=7-3
Whenever moving a number to the other side you have to change the sign .
2x= 4
x=2
Answer:
Solution given:
radius [r]=4
height [h]=5
we have
Surface area of cylinder=2πr(r+h)
=2π×4(4+5)
=<u>72πunits³ is a required volume.</u>
