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jek_recluse [69]
3 years ago
13

Help pls i have one chance left

Mathematics
1 answer:
emmasim [6.3K]3 years ago
5 0

Answer:

2^8x-3

Step-by-step explanation:

You might be interested in
Solve the following System of Three Equations: x−3y+z=−15<br> 2x+y−z=−2<br> x+y+2z=1
jeyben [28]

Answer:

x = -3 , y = 4 , z = 0

Step-by-step explanation:

Solve the following system:

{x - 3 y + z = -15

2 x + y - z = -2

x + y + 2 z = 1

Hint: | Choose an equation and a variable to solve for.

In the first equation, look to solve for z:

{x - 3 y + z = -15

2 x + y - z = -2

x + y + 2 z = 1

Hint: | Solve for z.

Subtract x - 3 y from both sides:

{z = 3 y + (-x - 15)

2 x + y - z = -2

x + y + 2 z = 1

Hint: | Perform a substitution.

Substitute z = -15 - x + 3 y into the second and third equations:

{z = -15 - x + 3 y

15 + 3 x - 2 y = -2

x + y + 2 (-15 - x + 3 y) = 1

Hint: | Expand the left hand side of the equation x + y + 2 (-15 - x + 3 y) = 1.

x + y + 2 (-15 - x + 3 y) = x + y + (-30 - 2 x + 6 y) = -30 - x + 7 y:

{z = -15 - x + 3 y

15 + 3 x - 2 y = -2

-30 - x + 7 y = 1

Hint: | Choose an equation and a variable to solve for.

In the second equation, look to solve for x:

{z = -15 - x + 3 y

15 + 3 x - 2 y = -2

-30 - x + 7 y = 1

Hint: | Isolate terms with x to the left hand side.

Subtract 15 - 2 y from both sides:

{z = -15 - x + 3 y

3 x = 2 y - 17

-30 - x + 7 y = 1

Hint: | Solve for x.

Divide both sides by 3:

{z = -15 - x + 3 y

x = (2 y)/3 - 17/3

-30 - x + 7 y = 1

Hint: | Perform a substitution.

Substitute x = (2 y)/3 - 17/3 into the third equation:

{z = -15 - x + 3 y

x = (2 y)/3 - 17/3

(19 y)/3 - 73/3 = 1

Hint: | Choose an equation and a variable to solve for.

In the third equation, look to solve for y:

{z = -15 - x + 3 y

x = (2 y)/3 - 17/3

(19 y)/3 - 73/3 = 1

Hint: | Isolate terms with y to the left hand side.

Add 73/3 to both sides:

{z = -15 - x + 3 y

x = (2 y)/3 - 17/3

(19 y)/3 = 76/3

Hint: | Solve for y.

Multiply both sides by 3/19:

{z = -15 - x + 3 y

x = (2 y)/3 - 17/3

y = 4

Hint: | Perform a back substitution.

Substitute y = 4 into the first and second equations:

{z = -x - 3

x = -3

y = 4

Hint: | Perform a back substitution.

Substitute x = -3 into the first equation:

{z = 0

x = -3

y = 4

Hint: | Sort results.

Collect results in alphabetical order:

Answer: {x = -3 , y = 4 , z = 0

6 0
3 years ago
What is an equation of the line that passes through the point (8,-2) and is perpendicular to the line 4x+3y=3
Zepler [3.9K]

Answer:

y = 3/4x - 8

Step-by-step explanation:

7 0
1 year ago
-3x-4y=12 just do it​
allochka39001 [22]

Answer: X intercept: (-4,0) Y Intercept: (0,-3)

Step-by-step explanation: i dont know if thats how it was suppose to be done or not but that is just the intercepts for it.

6 0
2 years ago
Read 2 more answers
Is 3z-1 in standard form?
babunello [35]

Answer:

Yes because

Step-by-step explanation:

Is 3z-1 in standard form?

Yes becausestandard form of a polynomial, the value in the power of the variable such as z in the equation reduces from left to right. Therefore, 3z - 1 is in standard form since the z term comes to the left of the constant term

7 0
3 years ago
How many milliequivalents of sodium chloride are contained with 3 L of normal saline?
AVprozaik [17]

Answer:

466mEq

Step-by-step explanation:

First, we need to know the concentration of NaCl in a normal saline solution, this is by definition 0.9%, meaning we have 0.9g of NaCl per 100ml of solution, we want to know how much NaCl we have in 3L (3000ml):

3000ml*\frac{0.9g}{100ml}=27g=27000mg

So, we have 27000mg in 3L of normal saline solution.

Now, acording to our milliequivalent (mEq) equation (mEq=\frac{mg}{pE}) where pE is de molecular mass of NaCl divided by their charges, in this case 1:

pE= \frac{23+35}{1}=\frac{58}{1} = 58

Finally we substitute in the mEq formula:

mEq=\frac{mg}{pE}=\frac{27000}{58}=466mEq

I hope you find this information useful! Good luck!

4 0
3 years ago
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