In each following pairs, state which one is more likely to give up electrons?

Chemistry

1 answer:

Y_Kistochka [10]4 years ago

8 0

Human hair. Human hair as energy because it is living so, it is most likely to give up electrons.

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How many grams of nitric acid HNO₃, are required to neutralize (completely react with) 4.30 grams of Ca(OH)2 according to the ac

Brrunno [24]

Answer:

7.32g of HNO3 are required.

Explanation:

1st) From the balanced reaction we know that 2 moles of HNO3 react with 1 mole of Ca(OH)2 to produce 2 moles of H2O and 1 mole of Ca(NO3)2.

From this, we find that the relation between HNO3 and Ca(OH)2 is that 2 moles of HNO3 react with 1 mole of Ca(OH)2.

2nd) This is the order of the relations that we have to use in the equation to calculate the grams of nitric acid:

• starting with the 4.30 grams of Ca(OH)2.

• using the molar mass of Ca(OH)2 (74g/mol).

• relation of the 2 moles of HNO3 that react with 1 mole of Ca(OH)2 .

• using the molar mass of HNO3 (63.02g/mol).

$4.30g\text{ Ca\lparen OH\rparen}_2*\frac{1\text{ mol Ca\lparen OH\rparen}_2}{74g\text{ Ca\lparen OH\rparen}_2}*\frac{2\text{ moles HNO}_3}{1\text{ mole Ca\lparen OH\rparen}_2}*\frac{63.02g\text{ HNO}_3}{1\text{ mole HNO}_3}=7.32g\text{ HNO}_3$

So, 7.32g of HNO3 are required.

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2 years ago

A 20 g piece of metal with specific heat 0.4 J/g.°C absorbs 3.9 kilojoules of heat,

Ket [755]

Answer:

given that

....the mass of the metal is 20g(0.02kg)

....specific heat capacity(c) is 0.4J/g°C

....ΔT=??

heat(Q)=3.9KJ(3900J)

Q=mcΔT

ΔT= Q/mc

.....=3900÷(20g x 0.4J/g°C)

.....=487.5°C

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3 years ago

Why is it preferable to allow cold water to enter at the bottom of a condenser and exit at the top?

harkovskaia [24]

In a distillation model, it is better to let the cold water enter the bottom of the condenser and exit at the top because this can lead to a better cooling effect.
When water enters from the bottom, they will stay longer in the condenser, thus the vapor in the condenser can be cooled back into liquid faster.
In addition, this method can also save the amount of water used, since they water can stay longer in the condenser.

5 0

4 years ago

If 16.4 grams of copper (II) bromide react with 22.7 grams of sodium chloride, how many grams of sodium bromide are formed?

fomenos

The amount of sodium bromide that would be formed from the reaction will be 7.5524 grams

<h3>Stoichiometric calculation</h3>

Looking at the equation of the reaction:

$CuBr_2 + 2NaCl --- > CuCl_2 + 2NaBr$