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2 years ago

PLEASE HELP!! WILL MARK BRAINLIEST

Chemistry

1 answer:

Sonja [21]2 years ago

4 0

Explanation:

A ____Chemical Reaction_______________________ is a well defined example of a chemical change. A chemical ___ _____chemical equation___________________ can be used to show the changes that occur in a chemical reaction. In a chemical reaction, the substance on the left side of the arrow are the starting substance. These substances are called ___Reactants________________________. The substances on the right side of the arrow are the substances that result from the reaction. These substances are called ____________Products_______________. The arrow is read as either produces or ______yields_____________________. According to the law of conservation of __________mass_________________, atoms are neither lost nor gained during a chemical reaction. This law is illustrated when a chemical equation is ________Balanced___________. When this is done, there will be the same number of ___________atoms________________ of each kind on both sides of the equation. In a chemical equation, the numbers that are placed in front of the symbols and the formulas are called ______________coefficients_____________. They are necessary to keep the ___________________________ of atoms in balance. There are several rules for balancing an equation. First, write the correct ____________(not so sure)_____________ for each reactant and product. Next, choose the coefficients that make the number of atoms of each _______elements(not so sure)________________ on each side of the equation equal. The correctly written formula should not be changed. If you change the formula of a substance, the equation is no longer ___________correct_____________. Changing a formula will indicate a ________Substance___________________ different than the one intended. To balance the equation Mg + O2 à MgO, first choose coefficients to make the number of atoms of each element on each side of the equation equal. You would need to place a coefficient of _________two___________

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</span>
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2- Cu- 2
3- N -3
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Manganese nodules are considered a valuable resource from the ocean floor because they are abundant and contain not only mangane

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What best describes how the behavior of rocks changes when they become deeply buried and placed under high levels of heat and pr

Debora [2.8K]

Answer:

They become ductile and deform plastically

Explanation:

When rocks are buried by the materials up to a greater depth, then the confining pressure increases significantly. This results in the ductile behavior of the rocks at such depth. These rocks are present in the ductile region where the depth is about more than 20 to 30 km. Here the rocks are subjected to extremely high pressure and temperature conditions, which favors the transformation of rocks into more higher-grade metamorphic rocks. It is also enhanced due to the geothermal gradient.

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Thus, the rocks become ductile and deform plastically at such conditions.

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3 years ago

If an ice cube weighing 25.0 g with an initial

riadik2000 [5.3K]

Answer:

∘

Explanation:

As far as solving this problem goes, it is very important that you do not forget to account for the phase change underwent by the solid water at

∘

to liquid at

∘

The heat needed to melt the solid at its melting point will come from the warmer water sample. This means that you have

−

(

)

, where

- the heat absorbed by the solid at

∘

- the heat absorbed by the liquid at

∘

- the heat lost by the warmer water sample

The two equations that you will use are

⋅

, where

- heat absorbed/lost

- the mass of the sample

- the specific heat of water, equal to

4.18

∘

- the change in temperature, defined as final temperature minus initial temperature

and

⋅

fus

, where

- heat absorbed

- the number of moles of water

fus

- the molar heat of fusion of water, equal to

6.01 kJ/mol

Use water's molar mass to find how many moles of water you have in the

100.0-g

sample

100.0

⋅

1 mole H

18.015

5.551 moles H

So, how much heat is needed to allow the sample to go from solid at

∘

to liquid at

∘

5.551

moles

⋅

6.01

mole

33.36 kJ

This means that equation

(

)

becomes

33.36 kJ

−

The minus sign for

is used because heat lost carries a negative sign.

So, if

is the final temperature of the water, you can say that

33.36 kJ

sample

⋅

sample

−

water

⋅

water

More specifically, you have

33.36 kJ

100.0

⋅

4.18

∘

⋅

(

−

)

∘

−

650

⋅

4.18

∘

⋅

(

−

)

∘

33.36 kJ

418 J

⋅

(

−

)

−

2717 J

⋅

(

−

)

Convert the joules to kilojoules to get

33.36

0.418

⋅

−

2.717

⋅

(

−

)

This is equivalent to

0.418

⋅

2.717

⋅

67.925

−

33.36

34.565

0.418

2.717

11.026

∘

Rounded to two sig figs, the number of sig figs you have for the mass of warmer water, the answer will be

∘

Explanation:

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3 years ago