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3 years ago

Do you think it is important to classify things

Chemistry

1 answer:

Dafna1 [17]3 years ago

7 0

nononono JUST NO NOOOOOOOOO

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If you can plz help ASAP Read the chemical equation.

Svetllana [295]

N2 + 3H2 = 2NH3

in this question, we are dealing with only NH3 and H2 so we only focus on that

since the ratio of H2 to 2NH3 is 3:2, we say that

3 liters of H2 = 2 liters of 2NH3

3.6 litres of H2 = x liters of 2NH3

We cross multiple to give:

3 × x = 3.6 × 2

3x = 7.2

Divide both sides by 3

x = 7.2 ÷ 3

x = 2.4liters

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3 years ago

Are mushroom producing spores asexual or sexual

Leto [7]

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4 years ago

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How many moles are in 4.6 x 10^19 atoms? <br><br> *#27 is the question

velikii [3]

There are 0.000076 moles in 4.6 x 10^19 atoms.

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3 years ago

What is the unit for particles of titanium iii oxide

Ket [755]

Answer:

Explanation:

6 0

3 years ago

CrO42- + NO+ 4H+NO3- + Cr3++ 2H2O In the above redox reaction, use oxidation numbers to identify the element oxidized, the eleme

BaLLatris [955]

Answer:

- Element oxidized: N.

- The element reduced: Cr.

- The oxidizing agent: Chromium.

- The reducing agent: Nitrogen.

- Formula of the oxidizing agent: (CrO₄)²⁻

- Formula of the reducing agent: NO.

- name of the element oxidized: nitrogen.

- name of the element reduced: chromium.

Explanation:

Hello,

In this case, the redox reaction is:

$(CrO_4)^{2-} + NO + 4H^+\rightarrow (NO_3)^- + Cr^{3+} + 2H_2O$

In such a way, each element has the following oxidation state distribution:

$(Cr^{6+}O_4)^{2-} + N^{2+}O^{2-} + 4H^+\rightarrow (N^{5+}O^{2-}_3)^- + Cr^{3+} + 2H_2^{+}O^{2-}$

Thus, it seen that:

- The oxidized element is nitrogen as its oxidation state changes from 2+ to 5+. In addition, it is the reducing agent since it undergoes oxidation.

- The reduced element is chromium as its oxidation state changes from 6+ to 3+. In addition, it is the oxidizing agent since it undergoes reduction.

Hence, in order to answer:

- Element oxidized: N.

- The element reduced: Cr.

- The oxidizing agent: Chromium.

- The reducing agent: Nitrogen.

- Formula of the oxidizing agent: (CrO₄)²⁻

- Formula of the reducing agent: NO.

- name of the element oxidized: nitrogen.

- name of the element reduced: chromium.

Best regards.

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3 years ago