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Margaret [11]
2 years ago
14

Chemistry LA

Chemistry
1 answer:
Gre4nikov [31]2 years ago
6 0

Answer:

44 g/mol

Explanation:

It should be CO2 for carbon dioxide

CO2= 12+2(16)=44

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Particle quantity/number of Cu(NO3)2
Murrr4er [49]

Answer:

Cupid nitrate is what I'm going for

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2 years ago
8.310x10^2 – 7.210x10^1<br><br>[?]x10^[?]​
alisha [4.7K]

Answer:

7.589\times 10^{2}

Explanation:

The expression can be solved mathematically as follows:

1) 8.310\times 10^{2}-7.210\times 10^{1} Given

2) 8.310\times 10^{1+1} - 7.210\times 10^{1} Definition of sum

3) (8.310\times 10^{1})\times 10^{1}-7.210\times 10^{1} a^{m+n} = a^{m}\cdot a^{n}/Associative property

4) (8.310\times 10^{1}-7.210)\times 10^{1} Distributive property

5) (83.100-7.210)\times 10^{1} Multiplication

6) 75.89\times 10^{1} Subtraction.

7) (7.589\times 10^{1})\times 10^{1} Multiplication/Associative property

8) 7.589\times (10^{1}\times 10^{1}) Associative property

9) 7.589\times 10^{2} a^{m+n} = a^{m}\cdot a^{n}/Result

7 0
2 years ago
A metallic conductor moving at a constant speed in a magnetic field may develop a voltage across it. this is an example of _____
marysya [2.9K]
A metallic conductor moving at a constant speed in a magnetic field may develop a voltage across it. This is an example of Motional emf
Hope this helps!
3 0
3 years ago
Calculate the pH and fraction of dissociation ( α ) for each of the acetic acid ( CH 3 COOH , p K a = 4.756 ) solutions. A 0.002
marysya [2.9K]

Answer:

The degree of dissociation of acetic acid is 0.08448.

The pH of the solution is 3.72.

Explanation:

The pK_a=4.756

The value of the dissociation constant = K_a

pK_a=-\log[K_a]

K_a=10^{-4.756}=1.754\times 10^{-5}

Initial concentration of the acetic acid = [HAc] =c = 0.00225

Degree of dissociation = α

HAc\rightleftharpoons H^++Ac^-

Initially

c

At equilibrium ;

(c-cα)                                cα        cα

The expression of dissociation constant is given as:

K_a=\frac{[H^+][Ac^-]}{[HAc]}

1.754\times 10^{-5}=\frac{c\times \alpha \times c\times \alpha}{(c-c\alpha)}

1.754\times 10^{-5}=\frac{c\alpha ^2}{(1-\alpha)}

1.754\times 10^{-5}=\frac{0.00225 \alpha ^2}{(1-\alpha)}

Solving for α:

α = 0.08448

The degree of dissociation of acetic acid is 0.08448.

[H^+]=c\alpha = 0.00225M\times 0.08448=0.0001901 M

The pH of the solution ;

pH=-\log[H^+]

=-\log[0.0001901 M]=3.72

3 0
3 years ago
I need help with this question
Leviafan [203]

Answer:

i do not know the answer but pls give a heart and five starts so i can ask questions pls

Explanation:

3 0
2 years ago
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