How do you factorise y-26

A pizza has a diameter of 14 inches what is the approximate circumference

Savatey [412]

To find the circumference of a circle you can use either of these equations
3.14 X Diameter or 2 X 3.14 X Radius. But in this case we will use the first one. So 3.14 X 14 = 47.6 so the circumference of this circle would be 47.6 inches.
I hope this helps :)

7 0

4 years ago

What is 2.05 rounded to one decimal place

FrozenT [24]

2.05 rounded to one decimal place is 2.1
Always round up at 5 when rounding.

7 0

4 years ago

The measure of angle θ is 3pi/2 . The measure of its reference angle is /, and tan θ is .

Sphinxa [80]

Answer:

Reference angle: $\frac{\pi}{2}$

$tan(\theta)=tan(\frac{3\pi}{2})$ is not defined.

Step-by-step explanation:

The angle $\theta$ goes from the positive x-axis to the negative y-axis.

Therefore the reference angle can be calculated as following:

$\frac{3\pi}{2}-\pi=\frac{\pi}{2}$

We know that $tan(\theta)$ is:

$tan(\theta)=\frac{sin(\theta)}{cos(\theta)}$

If $\theta=\frac{3\pi}{2}$ then $cos(\frac{3\pi}{2})=0$ , therefore $tan(\frac{3\pi}{2})$ is not defined, because the division by 0 is not defined.

8 0

3 years ago

Slove for x, please.

KATRIN_1 [288]

Answer:

I do not know

Step-by-step explanation:

6 0

3 years ago

Suppose that the distribution of typing speed in words per minute (wpm) for experienced typists using a new type of split keyboa

KengaRu [80]

Answer:

a. 0.5 or 50%

b. 0.496 or 49.6%

c. 0.8185 or 81.85%

d. Yes, it would be just 0.0013 or 0.13% of probability to find a typist whose speed exceeds 105 wpm

e. 0.0252 or 2.52%

f. The qualifying speed would be 47.4 wpm.

Step-by-step explanation:

a. Let's find the z-score this way:

μ = 60 σ= 15

z-score = (x - μ)/σ

z-score = (60 - 60)/15

z-score = 0

Now, let's calculate the p value for z-score = 0, using the z-table:

p (z=0) = 0.5 or 50%

b. z-score = (x - μ)/σ

z-score = (59.9 - 60)/15

z-score = -0.01

Now, let's calculate the p value for z-score = -.0.01, using the z-table:

p (z = -0.01) = 0.496 or 49.6%

If the question were less or equal than 60, a and b would have the same answer. But in this case, the question is "less than 60 wpm".

c.

z-score = (x - μ)/σ

z-score = (45 - 60)/15

z-score = - 1

Now, let's calculate the p value for z-score = -1, using the z-table:

p (z = -1) = 0.1587

z-score = (x - μ)/σ

z-score = (90 - 60)/15

z-score = 2

Now, let's calculate the p value for z-score = 2, using the z-table:

p (z = 2) = 0.9772

In consequence,

p (-1 ≤ z ≤ 2) = 0.9772 - 0.1587 = 0.8185 or 81.85%

d. z-score = (x - μ)/σ

z-score = (105 - 60)/15

z-score = 3

Now, let's calculate the p value for z-score = 3, using the z-table:

p (z = 3) = 0.9987

In consequence,

p (z > 3) = 1 - 0.9987 = 0.0013

Yes, it would be just a 0.13% of probability to find a typist whose speed exceeds 105 wpm.

e. z-score = (x - μ)/σ

z-score = (75 - 60)/15

z-score = 1

Now, let's calculate the p value for z-score = 1, using the z-table:

p (z = 1) = 0.8413

In consequence,

p (z > 1) = 1 - 0.8413 = 0.1587

and if the two typists are independently selected, then

p = 0.1587 * 0.1587

p = 0.0252 or 2.52%

f. p = 0.2, using the z-table, the z-score is -0.84, then:

z-score = (x - μ)/σ

-0.84 = (x - 60)/15

-12.6 = x - 60

-x = -60 + 12.6

-x = - 47.4

x = 47.4

The qualifying speed would be 47.4 wpm.

8 0

3 years ago