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bija089 [108]
2 years ago
10

Why does the satellite not fall while revolving the earth​

Physics
1 answer:
hoa [83]2 years ago
8 0

Answer:

Satellites don't fall from the sky because they are orbiting Earth. Even when satellites are thousands of miles away, Earth's gravity still tugs on them. Gravity--combined with the satellite's momentum from its launch into space--cause the satellite go into orbit above Earth, instead of falling back down to the ground.

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a 300-gram toy car and a 500-gram toy car are sitting on a shelf that is 2 meters highter than the floor. by what percent is the
andre [41]
We are given:

m1 = 300 grams
m2 = 500 grams
h1 = h2 = 2 meters

We have to determine the potential energy of both toy cars:

PE = mgh
PE1 = m1gh1
PE1 = 300 grams/1000g/kg * 9.81 m/s^2 * 2 meters
PE1 = 5.886 Joules

PE2 = m2gh2
PE2 = 500 grams/1000g/kg * 9.81 m/s^2 * 2 meters
PE2 = 9.81 Joules

PE2 - PE1 / PE2

9.81 - 5.886 Joules / 9.81 joules * 100 = 40.0%

Therefore, the 500-gram car is greater by 40% in terms of potential energy than the 300-gram car. This is because mass is directly proportional to the potential energy of an object. 

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3 years ago
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What is the mass of a vehicle that has 50,000 N and 25M/S/S
natali 33 [55]

Answer:

F = 1250000 N

Explanation:

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7 0
2 years ago
How did Robert Whittaker change classification?
larisa [96]
He reorganized life into five kingdoms
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A 2.0-kg block is on a perfectly smooth (frictionless) ramp that makes an angle of 30^\circ30 ​∘ ​​ with the horizontal. What is
Nastasia [14]

Answer:

Explanation:

Since the surface is frictionless therefore there will be no friction force on block but there will be weight of block which we can divide in to two components i.e. mgcosθ &mgsinθ which is perpendicular and parallel to the surface respectively.

In response to mgcosθ ramp will apply a normal force to the block which will be of equal magnitude to that of mgcosθ.

Therefore Ramp will apply a Force of mgcosθ on block where m is the mass of block.

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Length of the pipe = 0.39 m

Number of harmonics = 3

Now there are 3 loops so here we can say

3\times \frac{\lambda}{2} = 0.39

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now here at the center of the pipe it will form Node

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So distance between node and its nearest antinode will be

d = \frac{\lambda}{4}

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So the distance will be 6.5 cm

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3 years ago
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