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kherson [118]
2 years ago
6

What is simple machines and it type.I need it today please​

Physics
1 answer:
raketka [301]2 years ago
4 0

Simple machines are tools, devices or objects that are used to make work easier.

TYPES OF SIMPLE MACHINES.

  • Levers
  • Inclined Plane
  • Wedges
  • Screw
  • Pulley
  • Wheel & Axle

<u>T</u><u>H</u><u>E</u><u> </u><u>L</u><u>E</u><u>V</u><u>E</u><u>R</u><u>S</u>

A lever is simply a plank or ridge beam that is free to rotate on a pivot.

<u>P</u><u>A</u><u>R</u><u>T</u><u>S</u><u> </u><u>O</u><u>F</u><u> </u><u>A</u><u> </u><u>L</u><u>E</u><u>V</u><u>E</u><u>R</u><u> </u>

  1. Load
  2. Effort
  3. Fulcrum or pivot

<u>C</u><u>L</u><u>A</u><u>S</u><u>S</u><u>E</u><u>S</u><u> </u><u>O</u><u>F</u><u> </u><u>L</u><u>E</u><u>V</u><u>E</u><u>R</u><u>S</u>

THE FIRST CLASS LEVER

In this class, the FULCRUM is between the EFFORT and the LOAD. The mechanical advantage is more if the load is closer to the FULCRUM. Examples: seesaws, boat oars and crowbars.

THE SECOND CLASS LEVER

In this class, the LOAD is between the EFFORT and the FULCRUM. The mechanical advantage is more if the LOAD is closer to the FULCRUM. Example: wheelbarrow.

THE THIRD CLASS LEVER

In this class, the EFFORT is between the LOAD and the FULCRUM. The mechanical advantage is more if the EFFORT is closer to the LOAD. Example: garden shovel.

<u>T</u><u>H</u><u>E</u><u> </u><u>INCLINED</u><u> </u><u>PLANE</u><u> </u><u>OR</u><u> </u><u>RAMP</u>

An inclined plane is a simple machine with a sloping surface. It makes it easier for us to move objects from lower grounds to higher grounds.

<u>W</u><u>E</u><u>D</u><u>G</u><u>E</u><u>S</u>

A wedge is simply a triangular tool, often made of wood, stone, metal or plastic. It is thick at one end and tapers to a thin or sharp edge at the other end. Examples: knife, axe, doorstopper, nail, blade on the snow plough or farmer grader.

<u>PULLEY</u>

A pulley is simply a wheel with a groove in it, and a rope in the groove. It is used to lift heavy objects from the ground to high places.

<u>WHEEL</u><u> </u><u>&</u><u> </u><u>AXLE</u>

Involves two circular objects joined at the center. It works when force is applied to the wheel or when force is applied to the axle. Example: door knob.

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The characteristic of a circuit actually indicate how the circuit functions. When one designs a circuit they have a specific function in mind and must know how to combine components in order to fulfill this functions.
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A small metal ball is suspended from the ceiling by a thread of negligible mass. The ball is then set in motion in a horizontal
Gemiola [76]

Answer:

Time taken, T=2\pi \sqrt{\dfrac{l\ cos\theta}{g}}

Explanation:

It is given that, a small metal ball is suspended from the ceiling by a thread of negligible mass. The ball is then set in motion in a horizontal circle so that the thread’s trajectory describes a cone as shown in attached figure.

From the figure,

The sum of forces in y direction is :

T\ cos\theta-mg=0

T=\dfrac{mg}{cos\theta}

Sum of forces in x direction,

T\ sin\theta=\dfrac{mv^2}{r}

mg\ tan\theta=\dfrac{mv^2}{r}.............(1)

Also, r=l\ sin\theta

Equation (1) becomes :

mg\ tan\theta=\dfrac{mv^2}{l\ sin\theta}

v=\sqrt{gl\ tan\theta.sin\theta}...............(2)

Let t is the time taken for the ball to rotate once around the axis. It is given by :

T=\dfrac{2\pi r}{v}

Put the value of T from equation (2) to the above expression:

T=\dfrac{2\pi r}{\sqrt{gl\ tan\theta.sin\theta}}

T=\dfrac{2\pi l\ sin\theta}{\sqrt{gl\ tan\theta.sin\theta}}

On solving above equation :

T=2\pi \sqrt{\dfrac{l\ cos\theta}{g}}

Hence, this is the required solution.

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If an organism didn't have DNA, it would be missing which sign of life ? a, b , c
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Answer:

A

Explanation:

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Explanation:

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A 57-kg woman holds a 6-kg package as she stands within an elevator which briefly accelerates upward at a rate of 0.15g. Determi
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Answer:

R = 710.7N

L = 67.689 N

During gravity fall L = R = 0 N

Explanation:

So the acceleration that the elevator is acting on the woman (and the package) in order to result in a net acceleration of 0.15g is

g + 0.15g = 1.15g

The force R that the elevator exerts on her feet would be product of acceleration and total mass (Newton's 2nd law):

a(m + M) = 1.15g(57 + 6) = 1.15*9.81*63 = 710.7N

The force L that she exerts on the package would be:

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