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3 years ago

a bus traveling at 60m/s brakes and accelerates to a stop at a rate of -6m/s^2. how far did it travel while it stopped?

Physics

1 answer:

Licemer1 [7]3 years ago

6 0

Answer:

300 m

Explanation:

using constant acceleration equations:

v = vi + a * t, v = final velocity = 0m/s , vi = initial velocity = 60m/s,

a = acceleration = -6m/s², t = time

solve t

t = 10s

x = vi * t + .5 * a * t²

plug

x = 300 m

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Block A, with a mass of 4.0 kg, is moving with a speed of 2.0 m/s while block B , with a mass of 8.0 kg, is moving in the opposi

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Consider velocity to the right as positive.

First mass:
m₁ = 4.0 kg
v₁ = 2.0 m/s to the right

Second mass:
m₂ = 8.0 kg
v₂ = -3.0 m/s to the left

Total momentum of the system is
P = m₁v₁ + m₂v₂
= 4*2 + 8*(-3)
= -16 (kg-m)/s

Let v (m/s) be the velocity of the center of mass of the 2-block system.

Because momentum of the system is preserved, therefore
(m₁+m₂)v= -16
(4+8 kg)*(v m/s) = -16 (kg-m)/s
v = -1.333 m/s

Answer:
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3 years ago

If your heart is beating at 76 beats per minute what is the frequency of your heart's oscillations

PSYCHO15rus [73]

That would be a frequency of 1.2666... beats per second. This can be phrased as your heart beats at 1.27 Hz.

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4 years ago

A solution containing 10.0 g of an unknown liquid and 90.0 g water has a freezing point of -3.33 °C. Given Kf = 1.86 °C/m for wa

Fantom [35]

Answer:

62.06 g/mol

Explanation:

We are given that a solution containing 10 g of an unknown liquid and 90 g

Given mass of solute = $W_B$ =10 g

Given mass of solvent= $W_A$ =90 g

$k_f=1.86^{\circ}C/m$

Freezing point of solution =-3.33 $^{\circ}$ C

Freezing point of solvent = $0^{\circ}$ C

Change in freezing point =Depression in freezing point

=Freezing point of solvent - freezing point of solution=0+3.33= $3.33^{\circ}$

$\Delta T_f=\frac{W_B\times K_f\times 1000}{W_A\times M_B}$

$M_B=\frac{10\times 1.86\times 1000}{3.33\times 90}$

$M_B=62.06 g/mol$

Hence, molar mass of unknown liquid is 62.06g/mol.

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3 years ago

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As a rocket rises, its kinetic energy changes

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Transformed into potential energy

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4 years ago

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a steel ball rolls horizontally off the edge of a tabletop that is 1.0 m high. it strikes the floor at a point 2.0 m horizontall

Sauron [17]

The ball in the air is for 0.319 sec.

The horizontal pace of a projectile is regular (in no way converting in value), and there's a vertical acceleration because of gravity; its cost is 9.8 m/s/s, down, The vertical speed of a projectile changes via nine.8 m/s every second, The horizontal motion of a projectile is impartial to its vertical movement.

Projectile motion is a form of motion experienced with the aid of an object or particle that is projected in a gravitational field, such as from Earth's floor, and movements alongside a curved route below the action of gravity best.

Projectile motion is the movement of an object thrown (projected) into the air. After the initial force that launches the item, it most effectively reports the pressure of gravity. The object is known as a projectile, and its route is called its trajectory.

Calculate:-

H = ut + 1/2 gt²

Since the vertical initial velocity is 0.

H = 0 +gt²

t = $\sqrt{ \frac{H}{g}$

= $\sqrt{ \frac{1}{9.8}$

= 0.319 sec.

Learn more about projectile motion here:-brainly.com/question/10680035

#SPJ4

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1 year ago