Answer:
a=1.25m/s²
Explanation:
GIVEN DATA
vi=10m/s
vf=15m/s
S=5m
TO FIND
a=?
SOLUTION
by using third equation of motion
2as=(vf)²-(vi)²
2a(5m)=(15m/s)²-(10m/s)²
10m×a=225m²/s²-100m²/s²
10m×a=125m²/s²
a=
a=12.5m/s²
Answer:
The average speed of the cars is 50mph
Explanation:
Option C
The two kinds of motion are horizontal and vertical
1 volt = 1 joule per coulomb
It takes 1 joule of work to force a coulomb of charge enough closer to a charge
with the same sign to raise its potential 1 volt.
If you allow 1 coulomb of charge to fall to where its potential is 1 volt less,
it gives up 1 joule of energy.
Answer:
Hello
A. The muscle contracts causing the tendon to pull the bone.