Answer:

Explanation:
Let consider the observer as an inertial reference frame. The object is modelled after the Principle of Momentum Conservation:

The speed of the more massive piece is:

The kinetic energy added to the system is:
![\Delta K = \frac{1}{2}\cdot [(5.333\,kg)\cdot (0\,\frac{m}{s} )^{2}+(26.665\,kg )\cdot (31.202\,\frac{m}{s} )^{2}]-\frac{1}{2}\cdot (32\,kg)\cdot (26\,\frac{m}{s} )^{2}](https://tex.z-dn.net/?f=%5CDelta%20K%20%3D%20%5Cfrac%7B1%7D%7B2%7D%5Ccdot%20%5B%285.333%5C%2Ckg%29%5Ccdot%20%280%5C%2C%5Cfrac%7Bm%7D%7Bs%7D%20%29%5E%7B2%7D%2B%2826.665%5C%2Ckg%20%29%5Ccdot%20%2831.202%5C%2C%5Cfrac%7Bm%7D%7Bs%7D%20%29%5E%7B2%7D%5D-%5Cfrac%7B1%7D%7B2%7D%5Ccdot%20%2832%5C%2Ckg%29%5Ccdot%20%2826%5C%2C%5Cfrac%7Bm%7D%7Bs%7D%20%29%5E%7B2%7D)

Density = mass/volume, volume = mass/density.
Since the mass of the small cube equals 20 and the mass of the large cube is double it would be 40.
Now plug in volume = 40 g/(7.87 g/cm^3).
Thus giving you a volume 5.08 cm^3
Answer:
D-it's never acceptable to ignore rules and etiquette
Explanation:
Answer:
W = 0 J
Explanation:
The amount of work done by gas at constant pressure is given by the following formula:

where,
W = Work done by the gas
P = Pressure of the gas
ΔV = Change in the volume of the gas
Since the volume of the gas is constant. Therefore, there is no change in the volume of the gas:

<u>W = 0 J</u>
Answer:
I believe the answer is B.
Explanation:
Newton's First Law of Gravity states, "The greater the weight (or mass) of an object, the more inertia it has. Heavy objects are harder to move than light ones because they have more inertia.
"