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torisob [31]
3 years ago
13

What is the acceleration if velocity increases from 10 m/s to 15m/s after travelling a distance of 5 metre​

Physics
1 answer:
Semenov [28]3 years ago
8 0

Answer:

a=1.25m/s²

Explanation:

GIVEN DATA

vi=10m/s

vf=15m/s

S=5m

TO FIND

a=?

SOLUTION

by using third equation of motion

2as=(vf)²-(vi)²

2a(5m)=(15m/s)²-(10m/s)²

10m×a=225m²/s²-100m²/s²

10m×a=125m²/s²

a=\frac{125}{10}

a=12.5m/s²

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I've found a link that should assist you or answer your question.
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6 0
3 years ago
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Tom [10]

Answer:

4th answer

Explanation:

The gradient of a distance-time graph gives the speed.

gradient = distance / time = speed

Here, the gradient is a constant till 30s. So it has travelled at a constant speed. It means it had not accelarated till 30s. and has stopped moving at 30s.

6 0
2 years ago
Heres some earned points
egoroff_w [7]

Answer:

what do you mean by that.

5 0
2 years ago
Read 2 more answers
A cow wanders 30 m North, turns 22 degrees right of its original path, and wanders another 40 m. Find its total displacement.
scoundrel [369]

Answer:OB=58.3m

Explanation:

So here cow wanders 30m in north and turns 22 degrees in right side and moves 40m more, as shown in figure given.

now take the starting point as a origin such that cow moves in x-y co-ordinate axis.

As shown in figure length OA is the length when cow moves in north or y direction. Later she takes 22 degrees turn to right and moves 40m more.

So the final displacement is the length of cow from the origin that is length OB.

now co-ordinates of B are [40cos22°,40sin22°+30] i.e [37.084,44.984]

now displacement of cow= length of OB

                                           = \sqrt{[37.084]^{2}+[44.984]^{2}  }

                                           =\sqrt{3398.78}

                                     OB =58.3

                                         

7 0
1 year ago
What line of code will call force with a value of 10 for mass and a value of 9.81 for acceleration?
Kaylis [27]

Line of code will call force with a value of 10 for mass and a value of 9.81 for acceleration is force(10, 9.81).

<h3 /><h3>Line of code for force and acceleration</h3>
  • In mechanics, acceleration refers to the rate at which an object's velocity with respect to time varies.
  • Acceleration is a vector quantity (in that they have magnitude and direction).
  • The direction of an object's acceleration is determined by the direction of the net force acting on it.
  • Newton's Second Law states that the combined effect of two factors determines how much an item accelerates.
  • The size of the net balance of all external forces acting on the object is, in accordance with the materials used to create it.
  • It inversely proportional to its mass, whereas the magnitude of the net resultant force is directly proportional to the net force.

def force(mass, acceleration):

force_val = mass*acceleration

return force_val

10 is assigned to mass and 9.81 is assigned to acceleration

def force(10, 9.81)

So, Line of code will call force with a value of 10 for mass and a value of 9.81 for acceleration is force(10, 9.81).

Learn more about acceleration here:

brainly.com/question/460763

#SPJ4

7 0
1 year ago
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