Part a.
u = 0, the initial velocity
v = 60 mi/h, the final velocity
a = 2.35 m/s², the acceleration.
Note that
1 m = 1609.34 m.
Therefore
v = (60 mi/h)*(1609.34 m/mi)*(1/3600 h/s) = 26.822 m/s
Use the formula
v = u + at
(26.822 m/s) = (2.35 m/s²)*(t s)
t = 26.822/2.35 = 11.4 s
Answer: 11.4 s
Part b.
We already determined that v = 60 mi/h = 26.822 m/s.
t = 0.6 s
Therefore
(26.822 m/s) = (a m/s²)*(0.6 s)
a = 26.822/0.6 = 44.7 m/s²
Answer: 44.7 m/s²
The tensile stress of the wire supporting 2 kg mass is determined as 6.1 x 10⁷ N/m².
<h3>
Tensile stress of the wire</h3>
The tensile stress of the wire is calculated as follows;
σ = F/A
where;
A = πr² = πD²/4
where;
A = π x (0.64 x 10⁻³)²/4
A = 3.22 x 10⁻⁷ m²
σ = F/A = (mg)/A = (2 x 9.8)/( 3.22 x 10⁻⁷)
σ = 6.1 x 10⁷ N/m²
Learn more about tensile stress here: brainly.com/question/25748369
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Answer:
471 N
Explanation:
Weight is just another word for the force of gravity.
Weight is a force that acts at all times on all objects near Earth. The Earth pulls on all objects with a force of gravity downward toward the center of the Earth (g-9.81 m/s2)
so we can simply say
weight =mass * gravitaitonal acceleraition
= 48 * 9.81
=470.88 N
= 471 N
Answer:
<u>954.4m/s</u>
Explanation:
For a free falling object,it has constant acceleration and a changing velocity.
By using the velocity-time formula, the velocity can be obtained.
The height the rock travelled is the distance.
From,
Velocity (v) = Distance (d) / Time(t)
v = 3245m/3.4s
v = <u>954.4m/s</u>
That js the answer I got. Hope it's right.
