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3 years ago

Define unit of electric work (JOULE) in relation to quantity of charge and potential difference.

1 answer:

6 0

1 volt = 1 joule per coulomb

It takes 1 joule of work to force a coulomb of charge enough closer to a charge
with the same sign to raise its potential 1 volt.

If you allow 1 coulomb of charge to fall to where its potential is 1 volt less,
it gives up 1 joule of energy.

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A sky diver, with parachute unopened, falls 625 m in 15.0 s. Then she opens her parachute and falls another 362 m in 139 s. What

Jobisdone [24]

Answer:

$v_{avg} = 6.41 m/s$

Explanation:

Average velocity is defined as the ratio of total displacement of the motion and total time taken in that motion

here we know that initially the sky diver drops without opening parachute by total displacement 625 m

then she open her parachute and drop another 362 m

so first it took time t = 15 s to drop without open parachute

then it took t = 139 s to drop next displacement

so here total displacement is given as

$d = 625 m + 362 m$

total time is given as

$t = 15 s + 139 s$

so average velocity is given as

$v_{avg} = \frac{625 + 362}{15 + 139}$

$v_{avg} = 6.41 m/s$

4 0

3 years ago

A crane raises a crate with a mass of 75 kg to a height of 10 m. Given that the

Crazy boy [7]

Answer: C. 7,350 J

Explanation:

Just did it in Apex

7 0

3 years ago

A 47 kg mass is moving across a horizontal surface at 8 m/s. What is the force required to bring the mass to a stop in 4.1 secon

crimeas [40]

Answer:

Force = -91.7 Newton

Explanation:

Given the following data;

Mass = 47 kg

Time = 4.1 seconds

Initial velocity = 8 m/s

Since the object comes to a stop, its final velocity would be equal to zero.

To find the force required to bring it to stop;

First of all, we would determine the acceleration of the object;

Mathematically, acceleration is given by the equation;

$Acceleration (a) = \frac{final \; velocity - initial \; velocity}{time}$

Substituting into the equation;

$a = \frac{0 - 8}{4.1}$

$a = \frac{-8}{4.1}$

Acceleration, a = -1.95 m/s²

Next, we would determine the force required to bring the object to stop;

$Force = mass * acceleration$

$Force = 47 * -1.95$

Force = -91.65 ≈ 91.7 Newton

6 0

3 years ago

A rock is thrown straight downward from a tree limb with an initial velocity v0. The rock has constant downward acceleration of

viktelen [127]

Answer:

v₀ = 15 m/s

Explanation:

given,

initial velocity = v₀

down acceleration of rock = 10 m/s²

rock distance

S₄ = 7 x S₁

From kinematic equations

S = v₀ t+0.5 at²

at t = 1 s

S₁ = v₀ (1)+0.5 x 10 x 1²

S₁ = v₀+ 5......(1)

at t = 4 s

S₄ = v₀ (4)+0.5 x 10 x 4²

S₄ = 4 v₀+80.....(2)

from equation (1) and (2)

7( v₀ + 5 ) = 4 v₀ +80

3 v₀ = 80 - 35

3 v₀ = 45

v₀ = 15 m/s

3 0

3 years ago

g A projectile of mass 3 kg is launched horizontally from an initial height 3 m with an initial velocity 10 m/s. This velocity i

Ierofanga [76]

Answer:

The kinetic energy at ground will be "238.2 J".

Explanation:

The given values are:

mass,

m = 3 kg

Initial height,

h = 3 m

Initial velocity,

v = 10 m/s

By using the conservation of energy at points A and B,

⇒ $E_A=E_B$

⇒ $mgh+\frac{1}{2}mv^2=k_B$

On substituting the values, we get

⇒ $3\times 9.8\times 3+\frac{1}{2}\times 3\times (10)^2=k_B$

⇒ $88.2+0.5\times 3\times 100=k_B$

⇒ $88.2+150=k_B$

⇒ $238.2 =k_B$

8 0

3 years ago