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4 years ago

Define unit of electric work (JOULE) in relation to quantity of charge and potential difference.

1 answer:

6 0

1 volt = 1 joule per coulomb

It takes 1 joule of work to force a coulomb of charge enough closer to a charge
with the same sign to raise its potential 1 volt.

If you allow 1 coulomb of charge to fall to where its potential is 1 volt less,
it gives up 1 joule of energy.

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A light beam in glass (n = 1.5) reaches an air-glass interface, at an angle of 60 degrees from the surface. What is the angle of

tester [92]

Answer:

θ₂ = 35.26°

Explanation:

given,

refractive index of air, n₁ = 1

refractive index of glass, n₂ = 1.5

angle of incidence, θ₁ = 60°

angle of refracted light, θ₂ = ?

using Snell's Law

n₁ sin θ₁ = n₂ sin θ₂

1 x sin 60° = 1.5 sin θ₂

sin θ₂ = 0.577

θ₂ = sin⁻¹(0.577)

θ₂ = 35.26°

Hence, the refracted light is equal to θ₂ = 35.26°

7 0

3 years ago

What is the main reason why many nuclear power plants are located near bodies of water? to wash wastes out of the power plant to

Natalija [7]

Answer: to avoid problems with water supply

Explanation: power plant needs water to run

7 0

3 years ago

Read 2 more answers

Which of these help create radio waves?

inysia [295]

The one that help create radio waves is :
Changing electric and magnetic fields applied at right angles

Radio waves are transverse wave, which means that the oscillations occurring perpendicular to the direction of energy transfer

hope this helps

3 0

3 years ago

If an 83.00 g sample of Iron has a starting temperature of 297K and an ending temperature of 329K how much heat will be lost fro

diamong [38]

Question 1 :

m = mass of iron sample = 83

c = specific heat of iron sample = 0.450 J/g ⁰C

T₀ = initial temperature = 297 K

T = final temperature = 329 K

Q = heat lost

Heat lost is given as

Q = m c (T - T₀)

inserting the values

Q = (83) (0.450) (329 - 297) = 1195.2 J

Question 2 :

m = mass of sample = 59 g

c = specific heat of sample = ?

ΔT = change in temperature = 85 c

c = specific heat

Q = heat absorbed = 4814.4 J

Heat absorbed is given as

Q = m c

inserting the values

4814.4 = (59) (85) c

c = 0.96 J/g C

the sample is cholorofom

Question 3 :

m = mass of sample = 55 g

c = specific heat of sample = ?

T₀ = initial temperature = 78 c

T = final temperature = 95 c

Q = heat absorbed = 3908.3 J

Heat absorbed is given as

Q = m c (T - T₀)

inserting the values

3908.3 = (55) (95 - 78) c

c = 4.2 J/g C

the sample is water

4 0

3 years ago

"In analyzing distances by apply ing the physics of gravitational forces, an astronomer has obtained the expression

zavuch27 [327]

Answer:

The value of R is $1.72\times10^{11}\ m$ .

(B) is correct option.

Explanation:

Given that,

In analyzing distances by apply ing the physics of gravitational forces, an astronomer has obtained the expression

$R=\sqrt{\dfrac{1}{(\dfrac{1}{140\times10^{9}})^2-(\dfrac{1}{208\times10^{9}})^2}}$

We need to calculate this for value of R

$R=\sqrt{\dfrac{1}{(\dfrac{1}{140\times10^{9}})^2-(\dfrac{1}{208\times10^{9}})^2}}$

$R=1.89\times10^{11}\ m$

So, The nearest option of the value of R is $1.72\times10^{11}\ m$

Hence, The value of R is $1.72\times10^{11}\ m$ .

6 0

4 years ago