Answer: 224 cubic feet
Step-by-step explanation: If the base of the tank is 56 sq feet in<u> area </u> then the dimensions could be, (2,28) (4,14) (7,8) for example. However, it doesn't really matter. It's only important that the information we know is that it is area and there are two dimensions. Since volume is determined by base x width x height, we do 56 x 4. Or using one of the factored pairs that works, for example, 8 x 7 x 4 = 224.
When we Simplify [(x^2)^3 × 5x] / [6x^2 × 15x^3], the result obtained is (1/18)x^2
<h3>Data obtained from the question</h3>
- [(x^2)^3 × 5x] / [6x^2 × 15x^3]
- Simplification =?
<h3>How to simplify [(x^2)^3 × 5x] / [6x^2 × 15x^3]</h3>
[(x^2)^3 × 5x] / [6x^2 × 15x^3]
Recall
(M^a)^b = M^ab
Thus,
(x^2)^3 = x^6
- [(x^2)^3 × 5x] / [6x^2 × 15x^3] = [x^6 × 5x] / [6x^2 × 15x^3]
Recall
M^a × M^b = M^(a+b)
Thus,
x^6 × 5x = 5x^(6 + 1) = 5x^7
6x^2 × 15x^3] = (6×15)x^(2 + 3) = 90x^5
- [x^6 × 5x] / [6x^2 × 15x^3] = 5x^7 / 90x^5
Recall
M^a ÷ M^b = M^(a - b)
Thus,
5x^7 ÷ 90x^5 = (5÷90)x^(7 - 5) = (1/18)x^2
Therefore,
- [(x^2)^3 × 5x] / [6x^2 × 15x^3] = (1/18)x^2
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You put the values of x into the equation to work out y, so the y column would be -5, -1, 3, 7 (for question 6)
For question 7, the y column would be 2,2,0,-2
Use these values to draw the graphs :)
Answer:
-4 --8
-4+8
4
Step-by-step explanation:
