All categories

3 years ago

What is the answer to this

Mathematics

1 answer:

11Alexandr11 [23.1K]3 years ago

7 0

(3x²y⁴)⁴ / 9x²(y³)⁴

Simplify the numerators first.

3x⁶y⁸ / 9x²y7

Now, divide the two together, and cross out the exponents as you simplify them.

Now, divide 3 from 9, and get 3. Then, divide x⁶ from x² and get x⁴. Finally, you divide y⁸ from y⁷ and get y.

Put those all together :

1x⁴y / 3

Simplify.

$\frac{ x^{4} {y}}{3}$

~Hope I helped!~

You might be interested in

the hundreds digit of my number is greater than the 10 digit. the one digit is less than the ten digit. what could my number be

muminat

h > t, u < t can be written together either of these two ways:
u < t < h or h > t > u And it could be any of these 120 numbers:
210 310 320 321 410 420 421 430 431 432 510 520 521 530 531 532 540 541 542 543 610 620 621 630 631 632 640 641 642 643 650 651 652 653 654 710 720 721 730 731 732 740 741 742 743 750 751 752 753 754 760 761 762 763 764 765 810 820 821 830 831 832 840 841 842 843 850 851 852 853 854 860 861 862 863 864 865 870 871 872 873 874 875 876 910 920 921 930 931 932 940 941 942 943 950 951 952 953 954 960 961 962 963 964 965 970 971 972 973 974 975 976 980 981 982 983 984 985 986 987

6 0

3 years ago

PLEASE HELP!!!!

Lunna [17]

NOTES:

Given a quadratic function in standard format (y = ax² + bx + c), the direction of the parabola is as follows:

if "a" is positive, then opens UP
if "a" is negative, then opens DOWN

Given a quadratic function in standard format (y = ax² + bx + c), the vertex can be found as follows:

the Axis Of Symmetry (x-value) is: x = $\frac{-b}{2a}$
y-value is found by plugging in the AOS for "x" in the equation

****************************************************************************************

1) y = x² + 11x + 24

a = +1 so the parabola opens UP

x = $\frac{-b}{2a}$ = $\frac{-11}{2(1)}$ = $-\frac{11}{2}$

y = $(-\frac{11}{2})^{2}$ + 11 $(-\frac{11}{2} )$ + 24 = $-\frac{25}{4}$

vertex $(-\frac{11}{2}$ , $-\frac{25}{4})$ is in Quadrant 3 and is below the x-axis

This COULD be the graph of the rain gauge.

The graph should contain the vertex, x-intercepts (-3, 0) and (-8, 0), and y-intercept (0, 24)

******************************************************************************************

2) y = -x² - 6x - 8

a = -1 so the parabola opens DOWN

x = $\frac{-b}{2a}$ = $\frac{-(-6)}{2(-1)}$ = $\frac{6}{-2}$ = -3

y = -(-3)² - 6(-3) - 8 = -9 + 18 - 8 = 1

vertex (-3, 1) is in Quadrant 2 and is above the x-axis

This could NOT be the graph of the rain gauge.

The graph should contain the vertex, x-intercepts (-2, 0) and (-4, 0), and y-intercept (0, -8)

******************************************************************************************

3) y = x² - 2x + 3

a = 1 so the parabola opens UP

x = $\frac{-b}{2a}$ = $\frac{-(-2)}{2(1)}$ = $\frac{2}{2}$ = 1

y = (1)² - 2(1) + 3 = 1 - 2 + 3 = 2

vertex (1, 2) is in Quadrant 1 and is above the x-axis

This could NOT be the graph of the rain gauge.

The graph should contain the vertex, y-intercept (0, 3), and its mirror image (2, 3). There are no x-intercepts

******************************************************************************************

4) y = x² + 4x + 4

a = 1 so the parabola opens UP

x = $\frac{-b}{2a}$ = $\frac{-4}{2(1)}$ = -2

y = (-2)² + 4(-2) + 4 = 4 - 8 + 4 = 0

vertex (-2, 0) is in Quadrant 2 and is on the x-axis

This COULD be the graph of the rain gauge.

The graph should contain the vertex, y-intercept (0, 4), and its mirror image (-4, 4). The x-intercept is the vertex.

Compared to the other four graphs, this is most likely the equation for the rain gauge!

******************************************************************************************

5) y = 3x² + 21x + 30

a = +3 so the parabola opens UP

x = $\frac{-b}{2a}$ = $\frac{-21}{2(3)}$ = $-\frac{7}{2}$

y = 3 $(-\frac{7}{2})^{2}$ + 21 $(-\frac{7}{2} )$ + 30 = $-\frac{27}{4}$

vertex $(-\frac{7}{2}$ , $-\frac{27}{4})$ is in Quadrant 3 and is below the x-axis

This COULD be the graph of the rain gauge.

The graph should contain the vertex, x-intercepts (-2, 0) and (-5, 0), and y-intercept (0, 30)

*******************************************************************************************

4 0

3 years ago

Read 2 more answers

How do I show the relationship between the input and the output

alexgriva [62]

Answer:

Types of Relationships between the Input and Output

The scatter plot can be a useful tool in understanding the type of relationship that exist between the inputs (X’s) and the outputs (Y’s)

Step-by-step explanation:

1. No Relationship: The scatter plot can give an obvious suggestion if the inputs and outputs on the graph are not related. The points will be scattered throughout the graph with no particular pattern. For no relationship to exist, points have to be completely diffused. If some points are in concentration, then maybe a relationship does exist and our analysis has not been able to uncover it.

2. Linear and Non-Linear: A linear correlation exists when all the points are plotted close together. They form a distinct line. On the other hand points could be close together but they could form a relationship which has curves in it. The nature of the relationship has wide ranging implications.

3. Positive and Negative: A positive relationship between the inputs and the outputs is one wherein more of one input leads to more of an output. This is also known as a direct relationship.

On the other hand a negative relationship is one where more of one input leads to less of another output. This is also known as an inverse relationship.

4. Strong and Weak: The strength of the correlation is tested by how closely the data fits the shape. For instance if all the points are scattered very close together to form a very visible line then the relationship is strongly linear. On the other hand, if the relationship does not so obviously fit the shape then the relationship is weak.

I don't know if this was exactly what you were looking for; hope it is! :)

7 0

3 years ago

Two circles have the same radius. Complete the description for whether the combined area of the two circles is the same as the a

Elodia [21]

Answer:

see below

Step-by-step explanation:

A = pi r^2

If they have the same radius they have the same area

A two circles = pi r^2 +pi r^2

= 2 pi r^2

If we double the radius

A = pi (2r)^2

= pi 4r^2

The combined area of two circles is 1/2 the area as the area of a circle with twice the radius.

5 0

3 years ago

Read 2 more answers

Lewis is rolling a 10-sided die 250 times. Each side of the die is labeled with a number 1 – 10. Based on the theoretical probab

oksano4ka [1.4K]

75 time because the proabablity of rolling any number each time is 1/10 so 250/10=25 the mutiples of 3 in 1-10 are 3,6,9 so 3*25 =75 tmes

5 0

3 years ago

Read 2 more answers