The point-slope form of the equation for a line can be written as
... y = m(x -h) +k . . . . . . . for a line with slope m through point (h, k)
Your function gives
... f'(h) = m
... f(h) = k
a) The tangent line is then
... y = 5(x -2) +3
b) The normal line will have a slope that is the negative reciprocal of that of the tangent line.
... y = (-1/5)(x -2) +3
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You asked for "an equation." That's what is provided above. Each can be rearranged to whatever form you like.
In standard form, the tangent line's equation is 5x -y = 7. The normal line's equation is x +5y = 17.
4/13 because the absolute value would be itself since it is positive. If it was negative then the absolute value would be positive.
Answer:
So you would not be carried away by the tides
Step-by-step explanation:
hope this is what u want
I'd say B. but that's only because I divided the number of times he flipped the coin by the number of sides it has, 2, and came up with 246. The closest number on here to that is 231 or B. I hope I helped.
