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Answer:
The options e and d are correct.
Explanation:
Mass of NiO = 7.5 g
Moles of NiO =
Moles of sulfuric acid = n
Volume of sulfuric acid ,V= 50 mL = 0.050 L
Molarity of sulfuric acid ,M = 6 mol/L
According to reaction, 1 mole of NiO reacts with 1 mole of sulfuric acid.
Then 0.10 moles of NiO reacts with :
of sulfuric acid.
As we can see that sulfuric acid is in excess amount, so the amount of the product will depend upon amount of NiO.
According to reaction, 1 mole of NiO gives with 1 mole of .
Then 0.10 moles of NiO wil give :
of
.
Molar mass of = 154.75 g/mol
Mass of 0.10 moles of :
= 154.75 g/mol × 0.10 mol = 15.475 g
Theoretical mass of = 15.475 g
Experimental yield of = 17.4 g
Percentage yield :
Percentage yield of :
Moles of = 262.85 g/mol × 0.10 mol = 26.285 g
Experimental yield of = 17.4 g
Percentage yield of :