1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Alisiya [41]
3 years ago
12

A flask of ammonia is connected to a flask of an unknown acid HX by a 1.68 m glass tube (where "X" represents a halogen). As the

two gases diffuse down the tube, a white ring of NH4X forms 115 cm from the ammonia flask. Identify element X (Name or symbol).
Chemistry
1 answer:
LenKa [72]3 years ago
5 0

Answer:

Explanation:

white ring of NH₄X is formed . Here X is Cl and

NH₄X is NH₄Cl ( ammonium chloride )

The reaction is as follows

NH₃ + HCl = NH₄Cl ( white fume )

You might be interested in
Calculate the total volume of gas produced at 22 c and 1.02 atm by the complete decomposition of 11.83 g of potassium chlorate
Elis [28]
Use Ideal gas law to solve. PV=mRT you have pressure (1.02atm), temperature (295K or 22°C), mass of KClO3(11.83g) , and universal gas constant on a molar mass basis (R=R_bar/M). Just make sure you units are consistent and use the ideal gas equation to solve for Volume. M, should be the total Molar mass for KClO3.
6 0
3 years ago
Calculate the ph of an aqueous solution that is 0.045 m in hcl(aq) at 25°c
ivann1987 [24]
Remember that HCl is a strong acid will dissociate almost 100%
HCl + H₂O --> H₃O⁺ + Cl⁻

pH = -log[H₃O⁺]
pH = -log(0.045) = 1.35

(The rules for sig figs are that if you take the log of a number with x significant figures, then the result should have x significant decimal places.)

The pH is 1.35
4 0
4 years ago
Calculate the molar concentration of HA (90.2 g/mol) in a solution that has a specific gravity of 1.24 and is 64% HNO3 (w/w).​
ser-zykov [4K]

Answer:

Explanation:

Hello,

In this case, considering the given specific gravity we are to compute the density of the 64% HNO3 solution:

\rho=1.24*1g/mL=1.24g/mL

In such a way, since the given solution of nitric acid is 64 % by mass, we've got:

\frac{64gHNO_3}{100g\ solution}

Thus, by using the previously computed density and the molar mass of HA (90.2 g/mol) we can compute the required molar concentration as follows:

M=\frac{(100g-64g)HA}{100g\ solution}*\frac{1.24g\ solution }{1mL \ solution}*\frac{1000mL\ solution}{1L\ solution}*\frac{1molHA}{90.2gHA}   \\\\M=4.95M

Regards.

8 0
3 years ago
Gasoline has a density of 0.7197 grams per milliliter. Calculate the mass, in grams, of a sample of gasoline with a volume of 48
barxatty [35]

Answer:

34.9103 or 34.9 g

Explanation:

Remember Density is a broken heart: m/v.

In this scenario (Let x = # of grams in the sample of gasoline),

D = 0.7198 g/mL = x g / 48.5 mL

So,

(0.7198 g/mL) * (48.5 mL) = x g

x g = 34.9103 = 34.9 g (Accounting for Significant Figures)

8 0
2 years ago
A stiff outer layer that helps the cell hold its rigid shape. Can be made
nevsk [136]
I just got this question and it was lipids sorry if i’m wrong
8 0
3 years ago
Other questions:
  • What is the typical percentage (by mass of elements other than hydrogen and helium in stars that are forming right now in the vi
    11·1 answer
  • What is the difference between water and alcohol
    5·1 answer
  • The atomic number of oxygen is 8 because oxgen has
    6·1 answer
  • Solid potassium chlorate when heated yields potassium chloride + oxygen gas? Formula
    7·1 answer
  • Which type of bond is between magnesium and oxygen?
    7·2 answers
  • A chemistry student weighs out of sulfurous acid , a diprotic acid, into a volumetric flask and dilutes to the mark with distill
    13·1 answer
  • Para balancear una ecuacion quimica se cuenta el numero de:
    7·1 answer
  • What occurs to the particles in a fluid during convection ?
    5·1 answer
  • What is the pressure of 2.20 mol of a gas stored in a 4.5 L container at a temperature of 170 K? (Use PV=nRT and R = 8.314 L∙kPa
    9·1 answer
  • What is the name <br><br> H3C<br> CH<br> CH3<br> CH3
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!