how many grams of copper are required to replace 4.00 grams of silver nitrate which are dissolved in water
2 answers:
Answer:
0.7482 g grams of copper are required .Explanation:
Moles of silver nitrate =
According to reaction , 2 moles of silver nitrate reacts with 1 mol of copper.
Then 0.0235 mol of silver nitrate will react with:
of copper
Mass of 0.0117737 mol of copper = 0.117737 mol × 63.55 g/mol = 0.7482 g
0.7482 g grams of copper are required .
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I found a similar problem to this as shown in the attached picture to helpme answer the problem. We use the M₁V₁ = M₂V₂ formula, wherein M₁ is the concentration of the original CuSO₄ solution, V₁ is the volume of CuSO₄ in the cuvette, M₂ is the concentration of Cu²⁺ in the cuvette, and V₂ is the total volume in the cuvette.
For cuvette 1:
M₁V₁ = M₂V₂
(0.06)(4 mL) = (M₂)(6+4 mL)
M₂ = <em>0.024 M Cu²⁺</em>
For cuvette 2:
M₁V₁ = M₂V₂
(0.06)(7 mL) = (M₂)(7+3 mL)
M₂ = <em>0.042 M Cu²⁺</em>
For cuvette 1:
M₁V₁ = M₂V₂
(0.06)(4 mL) = (M₂)(6+4 mL)
M₂ = <em>0.024 M Cu²⁺</em>
For cuvette 2:
M₁V₁ = M₂V₂
(0.06)(7 mL) = (M₂)(7+3 mL)
M₂ = <em>0.042 M Cu²⁺</em>